[英]Can I access url kwargs in django template context processor?
urls.py
url(r'^(?i)(?P<slug>[a-zA-Z0-9_]+)$', views_search.index, name='articles'),
context_processor.py context_processor.py
def get_username(request, **kwargs):
print kwargs
slug = kwargs.get('slug')
return {
'slug': slug
}
But when i am running it, its printing empty dict and nothing is returned to the template. 但是当我运行它时,它打印空字典并且没有任何内容返回到模板。 I have added this in template context processors in setting.
我在设置中的模板上下文处理器中添加了这个。 How can I access kwargs here ?
我怎么能在这里访问kwargs?
If an url is resolved, the ResolverMatch
object is set as an attribute on the request: 如果解析了URL,则将
ResolverMatch
对象设置为请求的属性:
def get_username(request):
if hasattr(request, 'resolver_match'):
slug = request.resolver_match.kwargs.get('slug')
return {'slug': slug}
return {}
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