如何使用 kwargs 制作 URL

Question

This is my problem you have to use def func! and print is already defined

my_url(sidoname='seoul', key='asdf')
print example)
https://api.go.kr?sidoname=soeul&key=asdf&

you have to use

def my_url(**kwargs):

   print(my_url(sidoname='seoul', key='asdf'))

Answer 1

def my_url(**kwargs):
    return base_url + '&'.join(['{}={}'.format(key, value) for key, value in kwargs.items()])

print(my_url(sidoname='soeul', key='asdf'))

output

https://api.go.kr/?sidoname=soeul&key=asdf

Answer 2

**kwargs is a dictionary so you should iterate through keys and values and append them to the base url.

def url_builder(base_url: str = "https://api.go.kr?", **kwargs):
    for key, value in kwargs.items():
        base_url += key + "=" + value + "&"
    return base_url[:-1]

print(url_builder(sidoname='soeul', key='asdf'))

Outputs:

https://api.go.kr?sidoname=soeul&key=asdf