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如何计算特定时间段内的事件数

[英]How to calculate number of events during specific time period

I am trying to calculate the number of events (each row is an event) in "df2" within a time period defined by "df1". 我正在尝试在“ df1”定义的时间段内计算“ df2”中的事件数(每一行是一个事件)。 I am able to do this for the entire time period approximately 5 mins, however I would like to break the time period into smaller chunks (1 min) and do the same calculation 我可以在大约5分钟的整个时间段内执行此操作,但是我想将时间段分成较小的块(1分钟)并进行相同的计算

df1<- structure(list(Location = 1:10, Lattitude = c(57.140532, 57.140527, 
57.13959, 57.13974, 57.14059, 57.14058, 57.1398, 57.13989, 57.14158, 
57.14386), t_in = structure(c(1455626730, 1455627326, 1455628122, 
1455628644, 1455629174, 1455629708, 1455630230, 1455630765, 1455631396, 
1455631931), class = c("POSIXct", "POSIXt"), tzone = ""), t_out = structure(c(1455627047, 
1455627615, 1455628462, 1455628933, 1455629486, 1455630015, 1455630552, 
1455631070, 1455631719, 1455632242), class = c("POSIXct", "POSIXt"
), tzone = "")), .Names = c("Location", "Lattitude", "t_in", 
"t_out"), class = "data.frame", row.names = c(NA, -10L))

df2<- structure(list(date.time = structure(c(1455630964, 1455630976, 
1455630987, 1455630998, 1455631009, 1455631021, 1455631032, 1455631043, 
1455631054, 1455631066, 1455631077, 1455631088, 1455631099, 1455631111, 
1455631423, 1455631446, 1455631479, 1455631502, 1455631569, 1455631772
), class = c("POSIXct", "POSIXt"), tzone = ""), code = structure(c(2L, 
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 
2L, 2L, 2L), .Label = c("1003", "32221"), class = "factor"), 
rec_id = structure(c(2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 
2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("301976", 
"301978", "301985", "301988"), class = "factor"), Lattitude = c("57.14066", 
"57.14066", "57.14066", "57.14066", "57.14066", "57.14066", 
"57.14066", "57.14066", "57.14066", "57.14066", "57.14066", 
"57.14066", "57.14066", "57.14066", "57.141869", "57.141869", 
"57.141869", "57.141869", "57.141869", "57.141869"), Longitude = c("2.075702", 
"2.075702", "2.075702", "2.075702", "2.075702", "2.075702", 
"2.075702", "2.075702", "2.075702", "2.075702", "2.075702", 
"2.075702", "2.075702", "2.075702", "2.081576", "2.081576", 
"2.081576", "2.081576", "2.081576", "2.081576"), Location = list(
    8, 8, 8, 8, 8, 8, 8, 8, 8, 8, NA, NA, NA, NA, 9, 9, 9, 
    9, 9, NA)), .Names = c("date.time", "code", "rec_id", 
"Lattitude", "Longitude", "Location"), row.names = 94:113, class = "data.frame")

Function returns the location from df1 if the date.time in df2 lies between df1$t_in and df1$t_out. 如果df2中的date.time位于df1 $ t_in和df1 $ t_out之间,则函数从df1返回位置。 This may seem a round about way but enables later calculations outwith this code 这似乎是一种解决方法,但是可以使用此代码进行以后的计算

ids <- as.numeric(df1$Location)
f <- function(x){
  a <- ids[ (df1$t_in < x) & (x < df1$t_out) ]
  if (length(a) == 0) NA else a
}   

df2$Location <- lapply(df2$date.time, f)

the above returns a list, so need to turn it into numeric. 上面的代码返回一个列表,因此需要将其转换为数字。 bit of a faff but cant get round it 有点人事,但不能绕过它

df2$Location<- paste(df2$Location)
df2$Location<- as.numeric(df2$Location)

NA's are then removed as these lie outside the time periods defined in df1 and thus irrelevant. 然后删除NA,因为它们位于df1中定义的时间段之外,因此不相关。

df2<-df2[!is.na(df2$Location),]

Then calculate number of events (ie each row)for each rec_id and Location 然后为每个rec_id和Location计算事件数(即每一行)

library (plyr)
df3 <- ddply(df2, c("rec_id","Location"), function(df){data.frame (detections=nrow(df))})

  rec_id Location detections
1 301976        9          5
2 301978        8         10

...perfect! ...完善!

however I would like to do this for smaller time periods. 但是,我想在更短的时间内执行此操作。 Every minute to be exact. 每分钟都是准确的。 and the period should start from the t_in (df1)at each location through until t_out (df1). 并且该周期应从每个位置的t_in(df1)开始直到t_out(df1)。 I can do this with a lot of work in excel but surely it can be automated in R (it is a large dataset). 我可以在excel中完成很多工作,但是可以肯定的是,它可以在R中自动化(这是一个很大的数据集)。

so ultimately i can count the number of events(nrow) at each location for each 1 minute time period between t_in and t_out in df1 所以最终我可以在df1中的t_in和t_out之间的每1分钟时间段内计算每个位置的事件数(增加)

such as (just visual example not actual data): 例如(只是视觉示例,不是实际数据):

  rec_id Location  minute(or period) detections
 301976        9             1           1
 301976        9             2           2
 301976        9             3           0
 301976        9             4           0
 301976        9             5           2
 301978        8             1           4
 301978        8             2           3
 301978        8             3           1
 301978        8             4           0
 301978        8             5           2

i can create the intervals from the first location but im not sure how to apply this further 我可以从第一个位置创建间隔,但是我不确定如何进一步应用此间隔

seq(from = head(df1$t_in,1), to = head(df1$t_out,1) , by = "mins")

I think the following can be used to generate a new df1 data frame with the sequences split output and then you can apply the steps you go through above with the new df1 . 我认为以下内容可用于生成具有序列拆分输出的新df1数据帧,然后可以对新df1应用上面经过的步骤。

They can possibly be combined but I just wanted to make sure it actually gets you what you want. 它们可能可以合并,但是我只是想确保它确实可以为您提供所需的东西。

First we expand the time intervals in your original data frame and produce a list of the expanded periods. 首先,我们扩展原始数据帧中的时间间隔,并生成扩展周期的列表。 Each row in df1 becomes an element in a list. df1每一行都成为列表中的元素。

res1 <- sapply(1:nrow(df1), function(i) {
                 seq(from = df1$t_in[i], to = df1$t_out[i] , by = "mins")})

Then we convert the list of sequences to a data frame (two columns) 然后,我们将序列列表转换为数据框(两列)

res2 <- lapply(res1, function(x) { 
                 data.frame(t_in = x[1:(length(x)-1)], t_out=x[2:length(x)]) })

And finally we merge everything together 最后,我们将所有内容合并在一起

df1v2 <- Reduce(function(...) merge(..., all=T), res2)

Then (tweaking your code) 然后(调整您的代码)

ids <- seq_len(nrow(df1v2))
f <- function(x){
  a <- ids[ (df1v2$t_in < x) & (x < df1v2$t_out) ]
  if (length(a) == 0) NA else a
}   

df2$Location <- lapply(df2$date.time, f)

which yields 产生

              date.time  code rec_id Lattitude Longitude Location
94  2016-02-16 14:56:04 32221 301978  57.14066  2.075702       37
95  2016-02-16 14:56:16 32221 301978  57.14066  2.075702       37
96  2016-02-16 14:56:27 32221 301978  57.14066  2.075702       37
97  2016-02-16 14:56:38 32221 301978  57.14066  2.075702       37
98  2016-02-16 14:56:49 32221 301978  57.14066  2.075702       38
99  2016-02-16 14:57:01 32221 301978  57.14066  2.075702       38
100 2016-02-16 14:57:12 32221 301978  57.14066  2.075702       38
101 2016-02-16 14:57:23 32221 301978  57.14066  2.075702       38
102 2016-02-16 14:57:34 32221 301978  57.14066  2.075702       38
103 2016-02-16 14:57:46 32221 301978  57.14066  2.075702       NA
104 2016-02-16 14:57:57 32221 301978  57.14066  2.075702       NA
105 2016-02-16 14:58:08 32221 301978  57.14066  2.075702       NA
106 2016-02-16 14:58:19 32221 301978  57.14066  2.075702       NA
107 2016-02-16 14:58:31 32221 301978  57.14066  2.075702       NA
108 2016-02-16 15:03:43 32221 301976 57.141869  2.081576       39
109 2016-02-16 15:04:06 32221 301976 57.141869  2.081576       39
110 2016-02-16 15:04:39 32221 301976 57.141869  2.081576       40
111 2016-02-16 15:05:02 32221 301976 57.141869  2.081576       40
112 2016-02-16 15:06:09 32221 301976 57.141869  2.081576       41
113 2016-02-16 15:09:32 32221 301976 57.141869  2.081576       NA

I'm not sure if the boundary checks are correct (modify f ) but it looks as if you get whet you are after. 我不确定边界检查是否正确(修改f ),但是看起来好像在追赶。 How important is a speed-up? 提速有多重要?

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