在PHP中将字符串转换为JSON对象或数组
[英]Converting string to json object or array in php
问题描述
I have to make a web service. 
我必须做一个网络服务。 Therefore I referred some tutorials in the internet and came up with the following codes 因此，我参考了互联网上的一些教程，并提出了以下代码
index.php index.php
<html>
<head>
<title>Form page</title>
</head>
<body>
<form action="http://localhost:81/my%20web%20service/webservice" method="get">
Table name:<br>
<input type="text" name="s" value=""><br>
<input type="submit" value="Submit">
</form>
</body>
</html>
webservice.php webservice.php
<?php
include('connectdb.php');
$something = $_GET['s'];
$sqlcode = mysql_query("Select * from $something");
$jsonObj= array();
while($result=mysql_fetch_object($sqlcode))
{
$jsonObj[] = $result;
}
$final_res =json_encode($jsonObj) ;
echo $final_res;
?>
connectdb.php connectdb.php
<?php
$hostname="localhost";
$username="root"; //write your username
$password=""; //write your password
$db_name="webservice_trial"; //write your db name
$con=mysql_connect($hostname,$username,$password);
mysql_select_db($db_name,$con) or die ("Cannot connect the Database");
mysql_query("SET NAMES 'utf8'",$con);
?>
The above codes works fine. 上面的代码工作正常。 When I enter a name of a table from form.php, it will retrieve all tuples in that particular table. 当我从form.php输入表名时，它将检索该特定表中的所有元组。
Now what I want to do is to make data display on another page. 现在，我要做的是使数据显示在另一页上。 ie I want to transfer data from webservice.php to another page from json format. 即我想将数据从webservice.php传输到json格式的另一页。 so I edited my webservice.php as following 所以我如下编辑了我的webservice.php
webservice.php webservice.php
<?php
include('connectdb.php');
$something = $_GET['s'];
$sqlcode = mysql_query("Select * from $something");
$jsonObj= array();
while($result=mysql_fetch_object($sqlcode))
{
$jsonObj[] = $result;
}
$final_res =json_encode($jsonObj) ;
echo $final_res;
$jsonArray = (array) json_decode($final_res);
echo $jsonArray[0];
?>
it gives the following error 它给出了以下错误
[{"name":"hilton","town":"colombo","telephone":"774933705","description":"excellent"},{"name":"galadari","town":"colombo","telephone":"112894143","description":"best"},{"name":"mt. lavinia","town":"mt. lavinia","telephone":"773580324","description":"good"}]
Catchable fatal error: Object of class stdClass could not be converted to string in C:\\xampp\\htdocs\\json_folder\\my web service\\webservice.php on line 18 可捕获的致命错误：第18行的C：\\ xampp \\ htdocs \\ json_folder \\ my web service \\ webservice.php中无法将类stdClass的对象转换为字符串
2 个解决方案
解决方案1
1 2016-02-21 18:56:16
You can either change 你可以改变
$jsonArray = json_decode($final_res);
to 至
$jsonArray = json_decode($final_res, True);
or, to access the name of the first item use 或者，要访问第一项的名称，请使用
print $jsonArray[0]->name;
解决方案2
0 2016-02-21 19:05:22
Instead of trying to typecast the decoded string to an array, use this, which is the right way to do it. 与其尝试将解码后的字符串类型转换为数组，不如使用它，这是正确的方法。
$jsonArray = json_decode($final_res, TRUE);
Now, you will have an array, which you can echo or var_dump . 现在，您将拥有一个数组，可以echo或var_dump 。
var_dump($jsonArray);
As in your question, what your error says is that, you are trying to echo it as a variable, where what you are trying to echo is actually an object class. 就像在您的问题中一样，您的错误说明的是，您试图将其作为变量进行echo ，而您试图回显的实际上是对象类。 Probably because it isnt being typecasted. 可能是因为它没有被强制转换。
Advices: 忠告：
Please stop using
mysqlfunctions.请停止使用mysql函数。 Its deprecated.不推荐使用。 Use mysqliorPDO.使用mysqli或PDO。Read about SQL Injections.
了解有关SQL注入的信息。 Never trust userinputs. 永远不要相信用户输入。 Always sanitize them or use prepared statements. 始终对其进行消毒或使用准备好的语句。
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