Converting string to json object or array in php
Question
I have to make a web service. Therefore I referred some tutorials in the internet and came up with the following codes
index.php
<html>
<head>
<title>Form page</title>
</head>
<body>
<form action="http://localhost:81/my%20web%20service/webservice" method="get">
Table name:<br>
<input type="text" name="s" value=""><br>
<input type="submit" value="Submit">
</form>
</body>
</html>
webservice.php
<?php
include('connectdb.php');
$something = $_GET['s'];
$sqlcode = mysql_query("Select * from $something");
$jsonObj= array();
while($result=mysql_fetch_object($sqlcode))
{
$jsonObj[] = $result;
}
$final_res =json_encode($jsonObj) ;
echo $final_res;
?>
connectdb.php
<?php
$hostname="localhost";
$username="root"; //write your username
$password=""; //write your password
$db_name="webservice_trial"; //write your db name
$con=mysql_connect($hostname,$username,$password);
mysql_select_db($db_name,$con) or die ("Cannot connect the Database");
mysql_query("SET NAMES 'utf8'",$con);
?>
The above codes works fine. When I enter a name of a table from form.php, it will retrieve all tuples in that particular table.
Now what I want to do is to make data display on another page. ie I want to transfer data from webservice.php to another page from json format. so I edited my webservice.php as following
webservice.php
<?php
include('connectdb.php');
$something = $_GET['s'];
$sqlcode = mysql_query("Select * from $something");
$jsonObj= array();
while($result=mysql_fetch_object($sqlcode))
{
$jsonObj[] = $result;
}
$final_res =json_encode($jsonObj) ;
echo $final_res;
$jsonArray = (array) json_decode($final_res);
echo $jsonArray[0];
?>
it gives the following error
[{"name":"hilton","town":"colombo","telephone":"774933705","description":"excellent"},{"name":"galadari","town":"colombo","telephone":"112894143","description":"best"},{"name":"mt. lavinia","town":"mt. lavinia","telephone":"773580324","description":"good"}]
Catchable fatal error: Object of class stdClass could not be converted to string in C:\\xampp\\htdocs\\json_folder\\my web service\\webservice.php on line 18
2 answers
solution1
1 2016-02-21 18:56:16
You can either change
$jsonArray = json_decode($final_res);
to
$jsonArray = json_decode($final_res, True);
or, to access the name of the first item use
print $jsonArray[0]->name;
solution2
0 2016-02-21 19:05:22
Instead of trying to typecast the decoded string to an array, use this, which is the right way to do it.
$jsonArray = json_decode($final_res, TRUE);
Now, you will have an array, which you can echo or var_dump .
var_dump($jsonArray);
As in your question, what your error says is that, you are trying to echo it as a variable, where what you are trying to echo is actually an object class. Probably because it isnt being typecasted.
Advices:
Please stop using
mysqlfunctions. Its deprecated. UsemysqliorPDO.Read about SQL Injections. Never trust userinputs. Always sanitize them or use prepared statements.
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