在python中使用for循环和嵌套列表

Question

I am trying to add each row of nested loop independently in order to find averages. I am missing a detail which may or may not derail my whole code.The code should compute the average of a given row of scores but drops the lowest grade.

def printAverages():
scores = [[100,100,1,100,100],
          [20,50,60,10,30],
          [0,10,10,0,10],
          [0,100,50,20,60]]
total = 0
minValue = 100
counter = -1
for row in scores:
    counter = counter + 1
    for n in scores[0]:
        total = total+n
        if minValue > n:
            minValue = n
    total = total - minValue
    print("Average for row",counter,"is",total)
    total = 0

How do i make it so for n in score [0] takes the average of each row instead of only computing the average of the first row? I know that scores[0] commands the program to only read the first row, I just don't know how to change it.

Thank you

Answer 1

Remember, the XY problem .

# Sum of a list of numbers divided by the number of numbers in the list
def average(numbers):
    return sum(numbers)/len(numbers)

# This is your data
scores = [[100,100,1,100,100],
          [20,50,60,10,30],
          [0,10,10,0,10],
          [0,100,50,20,60]]

# enumerate() allows you to write FOR loops naming both the list element and its index
for (i, row) in enumerate(scores):
    print("Average for row ", i, "is ", average(row))

Keep in mind that Python supports functional programming and encourages the programmer to write pure functions when possible!

Answer 2

the statement for n in scores[0]: will only go through the first column.

What you want it to say is for n in row: . That will have it go through each row, one row per loop of the outer loop