[英]Changing even digits in a number to odd
I am trying to pick the even digits from a number and convert them to odd by adding 1 to it 我正在尝试从数字中选择偶数数字,并将其加1转换为奇数
example input/output 输入/输出示例
n = 258463, ans = 359573 n = 258463,ans = 359573
int n=26540;
System.out.println("n= "+n+", ans= "+even2odd(n));
n=9528;
System.out.println("n= "+n+", ans= "+even2odd(n));
public static int even2odd(int n)
{
while ( n > 0 ) {
if (n%2==0) {
n +=1;
}
System.out.print( n % 10);
n = n / 10;
}
int ans = n;
return ans;
}
as you can see right I managed to convert all the even digits to odd but i dont know how to reverse them back into order and output it in the right place 如您所见,我设法将所有偶数都转换为奇数,但我不知道如何将它们反转回顺序并在正确的位置输出
Aaaaaannnd一班轮到这里
int i = Integer.parseInt(Integer.toString(26540).replaceAll("2", "3").replaceAll("4", "5").replaceAll("6", "7").replaceAll("8", "9"));
You can do this: 你可以这样做:
public static int even2odd(int n)
{
StringBuilder result = new StringBuilder();
while(n > 0)
{
int firstDigit = n %10;
if(firstDigit%2==0)
++firstDigit;
result.append(firstDigit);
n = n/10;
}
return Integer.parseInt(result.reverse().toString());
}
How about: 怎么样:
String numString = n+"";
String outString = "";
for(int i=0; i<numString.length;i++){
int digit = Character.getNumericValue(numString.charAt(i));
if(digit%2==0) digit++;
outString+=digit;
}
int out = Integer.parseInt(outString);
If you are instructed not to use String or Integer. 如果指示您不要使用String或Integer。
public static int even2odd(int n) {
int ans = 0;
int place = 1;
while ( n > 0 ) {
if (n%2==0) {
n +=1;
}
ans = ans+((n%10)*place);
place = place*10;
n = n / 10;
}
System.out.print( ans);
return ans;
}
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