[英]Changing even digits in a number to odd
我正在嘗試從數字中選擇偶數數字,並將其加1轉換為奇數
輸入/輸出示例
n = 258463,ans = 359573
int n=26540;
System.out.println("n= "+n+", ans= "+even2odd(n));
n=9528;
System.out.println("n= "+n+", ans= "+even2odd(n));
public static int even2odd(int n)
{
while ( n > 0 ) {
if (n%2==0) {
n +=1;
}
System.out.print( n % 10);
n = n / 10;
}
int ans = n;
return ans;
}
如您所見,我設法將所有偶數都轉換為奇數,但我不知道如何將它們反轉回順序並在正確的位置輸出
Aaaaaannnd一班輪到這里
int i = Integer.parseInt(Integer.toString(26540).replaceAll("2", "3").replaceAll("4", "5").replaceAll("6", "7").replaceAll("8", "9"));
你可以這樣做:
public static int even2odd(int n)
{
StringBuilder result = new StringBuilder();
while(n > 0)
{
int firstDigit = n %10;
if(firstDigit%2==0)
++firstDigit;
result.append(firstDigit);
n = n/10;
}
return Integer.parseInt(result.reverse().toString());
}
怎么樣:
String numString = n+"";
String outString = "";
for(int i=0; i<numString.length;i++){
int digit = Character.getNumericValue(numString.charAt(i));
if(digit%2==0) digit++;
outString+=digit;
}
int out = Integer.parseInt(outString);
如果指示您不要使用String或Integer。
public static int even2odd(int n) {
int ans = 0;
int place = 1;
while ( n > 0 ) {
if (n%2==0) {
n +=1;
}
ans = ans+((n%10)*place);
place = place*10;
n = n / 10;
}
System.out.print( ans);
return ans;
}
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