Python：在for循环中打印两个列表

Question

I have two lists. 我有两个清单。

one=["first","second"]
two=[1,2]
for o in one:
    for t in two:
        print(o)
        print(t)

and the output is: 输出为：

first
1
first
2
second
1
second
2

Here is what the correct output should be: 这是正确的输出应该是：

first
1
2
second
1
2

There one more ,my professor has asked to print the output- 还有，我的教授要求打印输出-

first
1
second
2

Answer 1

I think this is what you want: 我认为这是您想要的：

for o in one:
    print(o)
    for t in two:
        print(t)

So that you only print the string number once per time you run the inner loop. 这样，每次运行内循环时，您只打印一次字符串号。

EDIT: 编辑：

you can do this: 你可以这样做：

both = zip(one, two)
for tup in both:
  for val in tup:
    print(val, end=' ')

Answer 2

for o in one:
    print(o)
    for t in two:
        print(t)

Answer 3

Just a slight change. 只是稍有变化。

    one=["first","second"]
    two=[1,2]
    for o in one:
        print(o)
        for t in two:
            print(t)

Answer 4

Your code should be this: 您的代码应为：

one=["first","second"]
two=[1,2]
for o in one:
    print(o)
    for t in two:
        print(t)