Python：在for循環中打印兩個列表

Question

我有兩個清單。

one=["first","second"]
two=[1,2]
for o in one:
    for t in two:
        print(o)
        print(t)

輸出為：

first
1
first
2
second
1
second
2

這是正確的輸出應該是：

first
1
2
second
1
2

還有，我的教授要求打印輸出-

first
1
second
2

Answer 1

我認為這是您想要的：

for o in one:
    print(o)
    for t in two:
        print(t)

這樣，每次運行內循環時，您只打印一次字符串號。

編輯：

你可以這樣做：

both = zip(one, two)
for tup in both:
  for val in tup:
    print(val, end=' ')

Answer 2

for o in one:
    print(o)
    for t in two:
        print(t)

Answer 3

只是稍有變化。

    one=["first","second"]
    two=[1,2]
    for o in one:
        print(o)
        for t in two:
            print(t)

Answer 4

您的代碼應為：

one=["first","second"]
two=[1,2]
for o in one:
    print(o)
    for t in two:
        print(t)