Java servlet如何处理以'/'结尾的URL？

Question

Usually, these two requests:

localhost:8080/test
localhost:8080/test/

have no difference.

However, when I add a servlet-mapping config:

<servlet-mapping>
    <servlet-name>default</servlet-name>
    <url-pattern>*.html</url-pattern>
</servlet-mapping> 

then

localhost:8080/test/

Does not work, it would return 404 error, I don't understand that I had added a config like this:

<servlet-mapping>
    <servlet-name>rest</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

<servlet>
    <servlet-name>rest</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            /WEB-INF/rest-servlet.xml,
            /WEB-INF/interceptor-servlet.xml,
            /WEB-INF/controller-servlet.xml,
        </param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

So, why would the request not go to this servlet, what is the magic in *.html ? The others like *.txt , *.jpeg would not cause this problem.

Answer 1

remove

<servlet-mapping>
   <servlet-name>default</servlet-name>
   <url-pattern>*.html</url-pattern>
</servlet-mapping> 

leave

<servlet-mapping>
    <servlet-name>rest</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

and let Spring distinguish between rest and html requests.