如何在Java中的Servlet中读取URL和打印
[英]how to read URL and Print in Servlet in java
问题描述
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.getWriter().append("Served at: ").append(request.getRequestURL());
System.out.println("Received Value: "+request.getRequestURL());
Utils.getDataFromFeedbackLink(request.getContextPath());
response.setContentType("text/html");
PrintWriter pw=response.getWriter();
pw.println("<html><body>");
pw.println("Welcome to servlet"+request.getRequestURL());
pw.println("</body></html>");
pw.close();
}
web.xml 
web.xml
<servlet>
<servlet-name>SubmitFeedbackServlet</servlet-name>
<display-name>SubmitFeedbackServlet</display-name>
<description></description>
<servlet-class>com.techjini.tfs.servlets.SubmitFeedbackServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>SubmitFeedbackServlet</servlet-name>
<url-pattern>/submitfeedback</url-pattern>
</servlet-mapping>
this is my Code of servlet get method : i want to print what ever request URL will be Like http://localhost:8080/TechJiniFeedbackSystem/submitfeedback/Hello servlet 这是我的servlet get方法代码：我想打印任何请求的URL都将像http：// localhost：8080 / TechJiniFeedbackSystem / submitfeedback / Hello servlet
then this URL should Print in my Consle i have used getContextPath and getRequestURL but non of these printing http://localhost:8080/TechJiniFeedbackSystem/submitfeedback/Hello servlet 那么此URL应该在我的Consle中打印，我已经使用过getContextPath和getRequestURL，但是这些都不打印http：// localhost：8080 / TechJiniFeedbackSystem / submitfeedback / Hello servlet
please suggest me where am doing wrong or suggest me to solve this issue . 请建议我哪里做错了，或者建议我解决这个问题。
1 个解决方案
解决方案1
1 2016-08-12 09:44:11
It's incredible easy: you must use getRequestURL from HttpServletRequest in your Servlet in doGet method 这非常容易：您必须在doGet方法的Servlet中使用HttpServletRequest的 getRequestURL
or for more info you can use this methods: getServletPath(), getContextPath and etc. 或获取更多信息，可以使用以下方法：getServletPath（），getContextPath等。
read more in specification: https://docs.oracle.com/cd/E17802_01/products/products/servlet/2.5/docs/servlet-2_5-mr2/javax/servlet/http/HttpServletRequestWrapper.html#getRequestURL() 在规范中阅读更多信息： https : //docs.oracle.com/cd/E17802_01/products/products/servlet/2.5/docs/servlet-2_5-mr2/javax/servlet/http/HttpServletRequestWrapper.html#getRequestURL（）
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