我想在手机充电时通知用户，例如DUbattery saver应用在手机充电时通过屏幕覆盖通知

Question

i want to notify the user when phone is charging,like DUbattery saver app notifies by screen overlay when phone is charging

 public void onReceive(Context context, Intent intent) {
    try {

        IntentFilter ifilter = new IntentFilter(Intent.ACTION_BATTERY_CHANGED);
        Intent batteryStatus = context.registerReceiver(null, ifilter);

        int status = batteryStatus.getIntExtra(BatteryManager.EXTRA_STATUS, -1);
        boolean isCharging = status == BatteryManager.BATTERY_STATUS_CHARGING ||
                status == BatteryManager.BATTERY_STATUS_FULL;

        if (isCharging == true) {
            Toast.makeText(context, "PLEASE UNPLUG", Toast.LENGTH_LONG).show();
        }
    }

i have implemented this code in broadcastreceiver,how can i notify the user , or by opening the the app when phone is charging

Answer 1

在广播接收器中收到回调时，请使用意图启动您的应用程序。

Answer 2

If your broadcast receiver is getting called properly than you can open your activity or application using startactivity() method.

Something like this :

startActivity(new Intent(getApplicationContext(), youractivityname.class).addFlags(Intent.FLAG_ACTIVITY_NEW_TASK));

Answer 3

If you want to open the activity, all you need to do is generate a intent for your activity.

Intent intent = new Intent(Context, YourActivityClass.class);
startActivity(intent);

If otherwise you want to notify the user with some notification, you can If you want further info about intents and how start your activity, you should create a notification:

NotificationCompat.Builder mBuilder =
    new NotificationCompat.Builder(context)
    .setSmallIcon(R.drawable.notification_icon)
    .setContentTitle("My notification")
    .setContentText("Hello World!");
// Sets an ID for the notification
int mNotificationId = 001;
// Gets an instance of the NotificationManager service
NotificationManager mNotifyMgr = 
        (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
// Builds the notification and issues it.
mNotifyMgr.notify(mNotificationId, mBuilder.build());

Take a look to Android documentation about intents or about notification[2].

Answer 4

To check the state of the battery(charging or not)..use this code..

public static boolean isConnected(Context context) {
    Intent intent = context.registerReceiver(null, new IntentFilter(Intent.ACTION_BATTERY_CHANGED));
    int plugged = intent.getIntExtra(BatteryManager.EXTRA_PLUGGED, -1);
    return plugged == BatteryManager.BATTERY_PLUGGED_AC || plugged == BatteryManager.BATTERY_PLUGGED_USB;
}

Then if this function returns true..show the notification by this code..

NotificationCompat.Builder builder = new NotificationCompat.Builder(this)
    .setSmallIcon(R.drawable.ic_launcher)
    .setContentTitle("Charging State")
    .setContentText("Your phone is charging");
NotificationManager notificationManager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
notificationManager.notify(1, builder.build());

Answer 5

First prepare broadcast receiver to listen for changes to ACTION_POWER_CONNECTED, and in turn flag the screen to stay on. Then in onReceive of Broadcast Receiver-

public void onReceive { public static boolean isConnected(Context context) { Intent intent = context.registerReceiver(null, new IntentFilter(Intent.ACTION_BATTERY_CHANGED)); int plugged = intent.getIntExtra(BatteryManager.EXTRA_PLUGGED, -1); return plugged == BatteryManager.BATTERY_PLUGGED_AC || plugged == BatteryManager.BATTERY_PLUGGED_USB; } }

After that just simply notify the user with notification

NotificationCompat.Builder builder = new NotificationCompat.Builder(context) .setSmallIcon(R.drawable.notification_icon) .setContentTitle("Phone Status") .setContentText("Charging");

int notificationId = 12345;

NotificationManager notificationManager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);

notificationManager.notify(notificationId, builder.build());