[英]don't match string in brackets php regex
I've been trying to use preg_replace() in php to replace string.我一直在尝试在 php 中使用 preg_replace() 来替换字符串。 I want to match and replace all 's' in this string, but I just came with solution only mathching 's' between 'b' and 'c' or 's' between > <.
我想匹配并替换此字符串中的所有 's',但我只是提供了解决方案,仅在 'b' 和 'c' 之间使用了 's' 或 > < 之间的 's'。 Is there any way I can use negative look behind not just for the character '>' but for whole string ?
有什么方法可以让我不仅对字符 '>' 而是对整个字符串使用负向外观吗? I don't want to replace anything in brackets.
我不想替换括号中的任何内容。
<text size:3>s<text size:3>absc
<text size:3>xxetxx<text size:3>sometehing
edit: just get 's' in >s< and in bsc.编辑:只需在 >s< 和 bsc 中获取 's'。 Then when I will change string for example from 's' to 'te', to replace 'te' in xtex and sometehing.
然后,当我将字符串例如从“s”更改为“te”时,以替换 xtex 中的“te”和一些东西。 So I was looking for regular expression to avoid replacing anything in <....>
所以我正在寻找正则表达式以避免替换 <....> 中的任何内容
You can use this pattern:您可以使用此模式:
$pattern = '/((<[^>]*>)*)([^s]*)s/';
$replace = '\1\3■'; # ■ = your replacement string
$result = preg_replace( $pattern, $replace, $str );
Pattern explanation:图案说明:
( # group 1:
(<[^>]*>)* # group 2: zero-or-more <...>
)
([^s]*) # group 3: zero-or-more not “s”
s # litterally “s”
If you want match case-insensitive, add a “i” at the end of pattern:如果您希望匹配不区分大小写,请在模式末尾添加“i”:
$pattern = '/((<[^>]*>)*)([^s]*)s/i';
Edit: Replacement explanation编辑:替换说明
In the search pattern we have 3 groups surrounded by round brackets.在搜索模式中,我们有 3 个用圆括号括起来的组。 In the replace string we can refer to groups by syntax
\\1
, where 1
is the group number.在替换字符串中,我们可以通过语法
\\1
来引用组,其中1
是组号。
So, replace string in the example means: replace group 1 with itself, replace group 3 with itself, replace “s” with desired replacement.因此,示例中的替换字符串表示:将组 1 替换为自身,将组 3 替换为自身,将“s”替换为所需的替换。 We don't need to use group 2 because it is included in group 1 (this due to regex impossibility to retrieve repeating groups).
我们不需要使用组 2,因为它包含在组 1 中(这是由于正则表达式无法检索重复组)。
In the demo string:在演示字符串中:
abs<text size:3>ssss<text size:3><img src="img"><text size:3>absc
└┘╵└───────────┘╵╵╵╵└───────────────────────────────────────┘└┘╵╵
└─┘└────────────┘╵╵╵└──────────────────────────────────────────┘
1 2 345 6
Pattern matches:模式匹配:
group 1 group 3 s
--------- --------- ---------
1 > 0 1 1
2 > 1 0 1
3 > 0 0 1
4 > 0 0 1
5 > 0 0 1
6 > 3 1 1
The last “c” is not matches, so is not replaced.最后一个“c”不匹配,因此不会被替换。
Use preg_match_all
to get all the s
letters and use it with flag PREG_OFFSET_CAPTURE
to get the indices.使用
preg_match_all
获取所有s
字母并将其与标志PREG_OFFSET_CAPTURE
一起使用以获取索引。
The regular expression $pat
contains a negative lookahead and lookbehind so that the s
inside the brackets expression is not matched.正则表达式
$pat
包含否定的前瞻和后视,因此括号表达式中的s
不匹配。
In this example I replace s
with the string 5
.在本例中,我将
s
替换为字符串5
。 Change to the string you want to substitute:更改为要替换的字符串:
<?php
$s = " <text size:3>s<text size:3>absc";
$pat = "/(?<!\<text )s(?!ize:3\>)/";
preg_match_all($pat, $s, $matches, PREG_OFFSET_CAPTURE);
foreach ($matches[0] as $match) {
$s[$match[1]] = "5";
}
print_r(htmlspecialchars($s));
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