C++，计算正负数并计算数字的平均值）编写一个程序，读取未指定数量的整数

Question

"Count positive and negative numbers and compute the average of numbers Write a program that reads an unspecified number of integers , determines how many positive and negative values have been read, and computes the total and average of the input values (not counting zeros). Your program ends with the input 0. Display the average as a double. where did i go wrong??

#include <iostream>
using namespace std;
int main()

{
            int num= 0;
            int sum=0;
            int pos=0;
            int neg=0;
            double ave=0;
            cout << "Enter an integer, the input ends if it is 0: " ;
            cin >> num ;
            if (num%10==10) {
                while (num!=0) {
                    num/=10;
                    if (num%10>0) {
                        pos++;
                    }
            else if (num%10<0) {
                neg++;
            }
            sum+=num;
                }
            ave= (double)sum/(pos+neg);
            }
            cout <<"The number of positives are " << pos <<endl;
            cout <<"The number of negatives are " << neg <<endl;
            cout <<"The total is " << sum << endl;
            cout <<"The average is "<< ave << endl;
            return 0;

 }

Answer 1

You can use char[] to read input. I have modified your program as follows;

int main()
{
    int sum=0;
    int pos=0;
    int neg=0;
    double ave=0;
    char arr[100] = {'\0',};

    std::cout << "Enter an integer, the input ends if it is 0: " ;  
    gets(arr);

    int index = 0;
    char ch[1];
    bool negativeNumber = false;

    while(true)
    {               
        ch[0] = arr[index++];
        if(ch[0] == ' ') // Check space and continue;
        {
            continue;
        }
        else if(ch[0] == '0' || ch[0] == '\0') // check for 0 or NULL and break;
        {
            break;
        }
        if(ch[0] == '-') // Set flag if "-ve"
        {           
            negativeNumber = true;
            continue;
        }

        int digit = atoi(ch);
        if(negativeNumber)
        {
            digit *= -1;
            negativeNumber = false;
        }
        if(digit > 0)
        {
            pos++;
        }
        else if(digit < 0)
        {
            neg++;
        }
        sum += digit;
    }
    ave= (double)sum/(pos+neg);

    cout <<"The number of positives are " << pos <<endl;
    cout <<"The number of negatives are " << neg <<endl;
    cout <<"The total is " << sum << endl;
    cout <<"The sverage is "<< ave << endl;

    return 0;
 }

Hope this helps.