C++，计算正负数并计算数字的平均值）编写一个程序，读取未指定数量的整数

Question

“计算正数和负数并计算数字的平均值编写一个程序，读取未指定数量的整数，确定读取了多少正负值，并计算输入值的总数和平均值（不计算零）。你的程序以输入 0 结束。将平均值显示为双精度。我哪里出错了？？

#include <iostream>
using namespace std;
int main()

{
            int num= 0;
            int sum=0;
            int pos=0;
            int neg=0;
            double ave=0;
            cout << "Enter an integer, the input ends if it is 0: " ;
            cin >> num ;
            if (num%10==10) {
                while (num!=0) {
                    num/=10;
                    if (num%10>0) {
                        pos++;
                    }
            else if (num%10<0) {
                neg++;
            }
            sum+=num;
                }
            ave= (double)sum/(pos+neg);
            }
            cout <<"The number of positives are " << pos <<endl;
            cout <<"The number of negatives are " << neg <<endl;
            cout <<"The total is " << sum << endl;
            cout <<"The average is "<< ave << endl;
            return 0;

 }

Answer 1

您可以使用char[]来读取输入。 我已将您的程序修改如下；

int main()
{
    int sum=0;
    int pos=0;
    int neg=0;
    double ave=0;
    char arr[100] = {'\0',};

    std::cout << "Enter an integer, the input ends if it is 0: " ;  
    gets(arr);

    int index = 0;
    char ch[1];
    bool negativeNumber = false;

    while(true)
    {               
        ch[0] = arr[index++];
        if(ch[0] == ' ') // Check space and continue;
        {
            continue;
        }
        else if(ch[0] == '0' || ch[0] == '\0') // check for 0 or NULL and break;
        {
            break;
        }
        if(ch[0] == '-') // Set flag if "-ve"
        {           
            negativeNumber = true;
            continue;
        }

        int digit = atoi(ch);
        if(negativeNumber)
        {
            digit *= -1;
            negativeNumber = false;
        }
        if(digit > 0)
        {
            pos++;
        }
        else if(digit < 0)
        {
            neg++;
        }
        sum += digit;
    }
    ave= (double)sum/(pos+neg);

    cout <<"The number of positives are " << pos <<endl;
    cout <<"The number of negatives are " << neg <<endl;
    cout <<"The total is " << sum << endl;
    cout <<"The sverage is "<< ave << endl;

    return 0;
 }

希望这可以帮助。