C++ ; 编写一个读取十个整数的程序

Question

编写一个程序，读取十个整数并输出所有大于零的数字之和，所有小于零的数字之和（将是负数或零），以及所有数字之和，无论是正、负或零。 用户只输入十个数字一次，用户可以按任意顺序输入它们。 您的程序不应要求用户分别输入正数和负数。 现在修改这个程序，使其输出所有正数的总和、所有正数的平均值、所有非正数的总和、所有非正数的平均值、所有正数和非正数的总和，以及输入的所有数字的平均值。

这是我到目前为止...

#include <iostream>
using namespace std;
int main ()
{
     int number, negative_sum=0, positive_sum=0, sum=0, average_neg, 
         average_pos, average;
     int count=0, positiveCount=0, negativeCount=0; 

     cout << "Please Input 10 whole numbers(Each number should be separated by space or Enter)\n";
     for(int i=0; i < 10; i++)
     {
         cin >> number;

     if (number >= 0 )
     {
         positive_sum += number;
         positiveCount++;  
     } 
     else     
     {
         negative_sum += number ; 
         negativeCount++; 
     } 
     }

     average_pos = positive_sum / positiveCount;
     average_neg = negative_sum / negativeCount; 
     sum = positive_sum + negative_sum;
     average = sum / count; 

     cout << "The Total sum of Positive Numbers is " << positive_sum << " and the average of \nThe postive numbers entered is ";
     cout << average_pos<< endl; 
     cout << "The Total sum of Negative Numbers is " << negative_sum << " and the average of \nThe negative numbers entered is ";
     cout << average_neg << endl; 
     cout << "The Total sum of numbers entered is " << sum << " and its average is "<< average << endl;

     system("PAUSE");
     return 0;
}

基本上它只是在我输入数字后多次打印“请输入 10 个整数（每个数字应以空格或 Enter 分隔）\\n”部分。

Answer 1

您的代码的问题在于， average_pos = positive_sum / positiveCount;行中出现零除以零除法average_pos = positive_sum / positiveCount; average = sum / count; 和average_neg = negative_sum / negativeCount; . 为了避免这种情况，您可以添加if条件，仅当positiveCount 、 negativeCount和count are greater than 0时才执行除法

此外，在您的代码中，您将sum除以count行average = sum / count; 但在您的代码中没有任何地方增加count 。 您的for循环也提前结束。

正确的修改代码：

#include <iostream>
using namespace std;


int main ()
{

int number, negative_sum=0, positive_sum=0, sum=0, average_neg=0, 
average_pos=0, average=0;
int count=0, positiveCount=0, negativeCount=0; 
cout << "Please Input 10 whole numbers(Each number should be separated by space or       Enter)\n";

for(int i=0;i<10;i++)
 {

 //cout<<"i is"<<i<<endl;
cin >> number;

if (number >= 0 )
 {
     positive_sum += number;
     positiveCount++;  count++;
 } 

 else     
 {
     negative_sum += number ; 
     negativeCount++; count++;
 }  
 }
if(positiveCount>0)
{
 average_pos = positive_sum / positiveCount;
}

if(negativeCount>0)
{ 
average_neg = negative_sum / negativeCount; 
}

sum = positive_sum + negative_sum;

if(count>0)
{
  average = sum / count;
} 

 cout<<average_pos;
 cout << "The Total sum of Positive Numbers is " << positive_sum << " and the average of   \nThe postive numbers entered is ";
 cout << average_pos<< endl; 
 cout << "The Total sum of Negative Numbers is " << negative_sum << " and the average of  \nThe negative numbers entered is ";
 cout << average_neg << endl; 
 cout << "The Total sum of numbers entered is " << sum << " and its average is "<< average << endl;

 system("PAUSE");
 return 0;
 }

Answer 2

#include <iostream>
using namespace std;
int main ()
{
int number, negative_sum=0, positive_sum=0, sum=0, average_neg = 0,
average_pos = 0, average = 0;
int count=0, positiveCount=0, negativeCount=0;
cout << "Please Input 10 whole numbers(Each number should be separated by space or Enter)\n";
for(int i=0; i < 10; i++)
{
cin >> number;
if (number >= 0 )
{
positive_sum += number;
positiveCount++;
}
else
{
negative_sum += number ;
negativeCount++;
}
}
average_pos = positive_sum / positiveCount;
average_neg = negative_sum / negativeCount;
sum = positive_sum + negative_sum;
average = sum / count;
cout << "The Total sum of Positive Numbers is " << positive_sum << " and the average of \nThe postive numbers entered is ";
cout << average_pos<< endl;
cout << "The Total sum of Negative Numbers is " << negative_sum << " and the average of \nThe negative numbers entered is ";
cout << average_neg << endl;
cout << "The Total sum of numbers entered is " << sum << " and its average is "<< average << endl;
system("PAUSE");
return 0;
}

Answer 3

尝试这个

#include <iostream>
using namespace std;
int main ()
{
     int number, negative_sum=0, positive_sum=0, sum=0, average_neg = 0, 
         average_pos = 0, average = 0;
     int count=0, positiveCount=0, negativeCount=0; 

 cout << "Please Input 10 whole numbers(Each number should be separated by space or Enter)\n";
  for(int i=0; i < 10; i++)
  {
     cin >> number;
     if (number >= 0 )
     {
         positive_sum += number;
         positiveCount++;  
     } 
     else     
     {
         negative_sum += number ; 
         negativeCount++; 
     } 
  }
  average_pos = positive_sum / positiveCount;
  average_neg = negative_sum / negativeCount; 
  sum = positive_sum + negative_sum;
  average = sum / count; 

 cout << "The Total sum of Positive Numbers is " << positive_sum << " and the average of \nThe postive numbers entered is ";
 cout << average_pos<< endl; 
 cout << "The Total sum of Negative Numbers is " << negative_sum << " and the average of \nThe negative numbers entered is ";
 cout << average_neg << endl; 
 cout << "The Total sum of numbers entered is " << sum << " and its average is "<< average << endl;

 system("PAUSE");
 return 0;
}

希望这可以帮助 ... ：）