如何在python中获取命令行参数（sys.argv）

Question

filename:test.py

import sys
print(sys.version)
print(sys.argv)

I typed python test.py 1 2 3 in the cmd console , it works well.

3.5.1 (v3.5.1:37a07cee5969, Dec  6 2015, 01:54:25) [MSC v.1900 64 bit (AMD64)]
['test.py', '1', '2', '3']

However , I type test.py 1 2 3 in the cmd console, it can only get the first argument.

3.5.0b4 (v3.5.0b4:c0d641054635, Jul 26 2015, 06:55:14) [MSC v.1900 32 bit (Intel)]
['E:\\Bin\\iproc\\test.py']

How can I get these arguments ?

Answer 1

Sounds like your Windows file association is bad. Make sure arguments are passed as %%* . Use the assoc and ftype commands in cmd.exe to check. For example:

ASSOC .py=Python.File
FTYPE Python.File="C:\Python35\python.exe" "%%1" %%*

Answer 2

Yes, my Windows file association is bad.I Checked the registry , and finally changed the registry . The problem is solved .

[HKEY_CLASSES_ROOT\\Applications\\python.exe\\shell\\open\\command] @="\\"c:\\\\bin\\\\python35\\\\python.exe\\" \\"%L\\" %*"