使用 sys.argv 将命令行 arguments 传递给 python 脚本

Question

I know this question has been asked in various variations but none of them seem to work for my specific case:

(btw all mentioned files are in my PATH)

I have a simple python script called test.py:

import sys

print('Hello world!')
print(sys.argv)

counter = 0

while True:
    counter +=1

The counter is just there to keep the command window open so don't worry about that.

When I enter

test.py test test 

into cmd I get the following output:

Hello world!
['C:\\Users\\path\\to\\test.py']

For some reason unknown to me the two other commands (sys.argv[1] and sys.argv[2]) are missing.

However when I create a.bat file like this:

@C:\Users\path\to\python.exe C:\Users\path\to\test.py %*

and call it in cmd

test.bat test test

I get my desired output:

Hello world!
['C:\\Users\\path\\to\\test.py', 'test', 'test']

I've read that the

%*

in the.bat file means that all command line arguments are passed to the python script but why are exactly these arguments not passed to the python script when I explicitly call it in cmd?

From what I've read all command line arguments entered after the script name should be passed to said script but for some reason it doesn't work that way.

What am I overlooking here?

Answer 1

I'm guessing that you need to actually run the script through the command line with C:\Users\path\to\python.exe test.py test test .

I'm not sure how Windows handles just test.py test test but from my limited experience it is probably just trying to open all 3 of those files. Since the first one ( test.py ) has a .py extension, it is opened with the Python Interpreter and is run automatically. The other two are not actually being passed in as an argument.