从文件夹中的所有文档中打印特定行

Question

I want to print all the lines that contains "testing.$" from all folder's files.

I am trying the following command, but I am getting a error. What am I missing?

find ./* -type f -exec grep -l testing.$ {} \\ | grep -n ^ | grep ^Linha_do_Arquivo: | cut -d: -f2;

find: missing argument: '-exec'

Answer 1

You don't need find for this.
With grep only:

grep -rh "testing.$" .

-h hides the filename in the output. Omit it if you want to output it as well.