I want to print all the lines that contains "testing.$" from all folder's files.
I am trying the following command, but I am getting a error. What am I missing?
find ./* -type f -exec grep -l testing.$ {} \\ | grep -n ^ | grep ^Linha_do_Arquivo: | cut -d: -f2;
find: missing argument: '-exec'
You don't need find
for this.
With grep
only:
grep -rh "testing.$" .
-h
hides the filename in the output. Omit it if you want to output it as well.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.