随机数生成器仅打印一个数字

Question

This is the code I have so far:

 from quick_pick import quick_pick
    def main():
     LIMIT = 67
     number = 9
     list_1 = []*number
     quick_pick(number, LIMIT, list_1)
     print (list_1)
     main()

import random
def quick_pick(n,limit,lottery):
    main_count = 0
    while main_count <n:
        lotto_numbers = random.randint(1, limit)
        if lotto_numbers not in lottery:
            lottery.append(lotto_numbers)
            main_count += 1
            return (lottery * n)

but when I run it I get this: [21]

Im not sure how to get all 9 numbers to show up in the list so I can print it. If someone could help it would be appreciated as this is for part of my assignment and I need it to do the rest of it.

Answer 1

You can use random.sample to pick the numbers:

limit = 67
n = 9
print(random.sample(range(1, limit + 1), n)) # [49, 32, 66, 57, 25, 9, 22, 4, 48]

Answer 2

Fix you indentation, lose the * n , and viola(!), your code works:

def quick_pick(n,limit,lottery):
    main_count = 0
    while main_count <n:
        lotto_numbers = random.randint(1, limit)
        if lotto_numbers not in lottery:
            lottery.append(lotto_numbers)
            main_count += 1
    return lottery

>>> quick_pick(number,LIMIT,list_1)
[44, 43, 62, 13, 11, 25, 36, 29, 15]

The problem was, as you can see, the fact that you return after finding the first number to add to your lottery . You need to wait until it is filled up. Also multiplying by n (9) doesn't make much sense.

Answer 3

Another way to get random numbers following some particular distribution is to use the probability distributions directly..

Example:

import numpy as np

nums = np.random.uniform(-1, 1, (100, 2))

This will generate a hundred 2-dimensional points in the range (-1, 1) from the underlying uniform distribution (all the numbers in the range have the same probability of being picked).