简体   繁体   English

计数,总和在MySQL的主表(联合)和它的左表

[英]count,sum on both main table(union) and its left table in mysql

SELECT pa.prid,pa.prodid,pa.prva, ps.psna,ps.psnamid,ps.psval 
    FROM ( SELECT pid,prodid,count(prodid) as prid , 
          sum(prval) as prva
          FROM prodarpa 
          WHERE fcl = 1  GROUP BY prodid
    UNION SELECT pid,prodid,count(prodid) as prid , 
          sum(prval) as prva
          FROM prodarpb 
          WHERE fcl = 1  GROUP BY prodid ) AS pa 
    LEFT JOIN (SELECT psid,psnamid,count(psnamid) as psna,SUM(psvalue) as psval 
               FROM prosection GROUP BY psnamid ) AS ps
               ON ( pa.pid = ps.psid ) 

Hence i want result as below : 因此我想要如下结果:

pa.prid | pa.prodid | pa.prva | ps.psna | ps.psnamid | ps.psval 
 193        3           300      193         2          499
 200        5           100       0          0           0
  0         0            0       201         8          300
 163        10          678      163         5          453

What i mean is if pa.prid value is not in ps.psna then it should show 0 value in each column of ps table and same on another way 我的意思是,如果pa.prid值不在ps.psna中,则它应该在ps表的每一列中显示0值,并且在另一种方式上相同

but its not happening 但它没有发生

Without data to work from this is guesswork. 如果没有数据,这是一种猜测。

SELECT
      pa.prid
    , pa.prodid
    , pa.prva
    , ps.psna
    , ps.psnamid
    , ps.psval
FROM (
      SELECT
            pid
          , prodid
          , COUNT(prodid) AS prid
          , SUM(prval) AS prva
      FROM (
            SELECT
                  pid
                , prodid
                , prval
            FROM prodarpa
            WHERE fcl = 1
            UNION ALL
                  SELECT
                        pid
                      , prodid
                      , prval
                  FROM prodarpb
                  WHERE fcl = 1
            ) AS s
      GROUP BY
            pid
          , prodid
      ) AS pa
      LEFT JOIN (
            SELECT
                  psid
                , psnamid
                , COUNT(psnamid) AS psna
                , SUM(psvalue) AS psval
            FROM prosection
            GROUP BY
                  psid
                , psnamid
      ) AS ps ON (pa.pid = ps.psid)

Take care when using group by that you always specify ALL non-aggregating columns . 使用group by时请务必始终指定ALL非聚合列 MySQL does provide for a syntax where this isn't required - however the results of using that syntax are not reliable, and the syntax is only allowed if ONLY_FULL_GROUP_BY is enabled. MySQL确实提供了不需要的语法-但是使用该语法的结果并不可靠,并且仅在启用ONLY_FULL_GROUP_BY的情况下才允许使用该语法。

see: https://dev.mysql.com/doc/refman/5.0/en/group-by-handling.html 参见: https : //dev.mysql.com/doc/refman/5.0/en/group-by-handling.html

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM