[英]count,sum on both main table(union) and its left table in mysql
SELECT pa.prid,pa.prodid,pa.prva, ps.psna,ps.psnamid,ps.psval
FROM ( SELECT pid,prodid,count(prodid) as prid ,
sum(prval) as prva
FROM prodarpa
WHERE fcl = 1 GROUP BY prodid
UNION SELECT pid,prodid,count(prodid) as prid ,
sum(prval) as prva
FROM prodarpb
WHERE fcl = 1 GROUP BY prodid ) AS pa
LEFT JOIN (SELECT psid,psnamid,count(psnamid) as psna,SUM(psvalue) as psval
FROM prosection GROUP BY psnamid ) AS ps
ON ( pa.pid = ps.psid )
因此我想要如下结果:
pa.prid | pa.prodid | pa.prva | ps.psna | ps.psnamid | ps.psval
193 3 300 193 2 499
200 5 100 0 0 0
0 0 0 201 8 300
163 10 678 163 5 453
我的意思是,如果pa.prid值不在ps.psna中,则它应该在ps表的每一列中显示0值,并且在另一种方式上相同
但它没有发生
如果没有数据,这是一种猜测。
SELECT
pa.prid
, pa.prodid
, pa.prva
, ps.psna
, ps.psnamid
, ps.psval
FROM (
SELECT
pid
, prodid
, COUNT(prodid) AS prid
, SUM(prval) AS prva
FROM (
SELECT
pid
, prodid
, prval
FROM prodarpa
WHERE fcl = 1
UNION ALL
SELECT
pid
, prodid
, prval
FROM prodarpb
WHERE fcl = 1
) AS s
GROUP BY
pid
, prodid
) AS pa
LEFT JOIN (
SELECT
psid
, psnamid
, COUNT(psnamid) AS psna
, SUM(psvalue) AS psval
FROM prosection
GROUP BY
psid
, psnamid
) AS ps ON (pa.pid = ps.psid)
使用group by时请务必始终指定ALL非聚合列 。 MySQL确实提供了不需要的语法-但是使用该语法的结果并不可靠,并且仅在启用ONLY_FULL_GROUP_BY的情况下才允许使用该语法。
参见: https : //dev.mysql.com/doc/refman/5.0/en/group-by-handling.html
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