[英]1-liner regex to sum up numbers in a txt file
Just started learning python and wonder how does one sum up all the numbers in a txt file with regex and list compression. 刚开始学习python,想知道如何用正则表达式和列表压缩将txt文件中的所有数字相加。
I wrote the following but not sure how to avoid adding up numbers from empty lists in the findall search: 我写了以下内容,但不确定如何避免在findall搜索中将空列表中的数字相加:
import re
print (sum([int(num[0]) for num[0] in re.findall('[0-9]+', open('xxx.txt').read().split())]))
You don't need to split the input data since re.findall
should work on fileobj.read()
. 您不需要拆分输入数据,因为
re.findall
应该适用于fileobj.read()
。 And also don't specify the index on the intermediate variable while iterating over the resultant list of re.findall
. 并且在迭代
re.findall
的结果列表时,也不要在中间变量上指定索引。
print (sum(int(num) for num in re.findall('[0-9]+', open('xxx.txt').read())))
With \\d+
you will not have empty strings. 使用
\\d+
您将没有空字符串。 With map you will convert all your strings to integer and then sum them up with sum(). 使用map时,您会将所有字符串转换为整数,然后使用sum()求和。
print(sum(map(int, re.findall('\d+', open('xxx.txt').read()))))
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