Javascript正则表达式匹配至少一个以数字开头的单词跨越多个单词但至少有两个单词

Question

I am using Javascript Regex. I have an input field which should pass only the follwing condition

• Value should have only alphabets and numbers
• Value Should have at least two words(can have more than two)
• only One word Should have number(one or more) in the beginning
• Can allow spaces at the end

Please Help on this as I am new to Regex.

I tried with the below code. It worked for two words but it is not allowing more than two words. /^[\\d]+[a-zA-Z]*\\s+[a-zA-Z]+$|^[a-zA-Z]+\\s+\\b[\\d]+[a-zA-Z]*\\b$/

Answer 1

Using positive lookahead you can use this regex:

/^^(?=.*\b\d[a-z\d]*\b)(?:\b[a-z\d]+\b[ \t]*){2,}$/i

RegEx Demo

(?=.*\\b\\d[az\\d]*\\b) is positive lookahead to ensure there is at least one woth that starts with a digit.

Answer 2

试试这个正则表达式。

/^[\d]+[a-zA-Z]*\s+[a-zA-Z]+$|^([a-zA-Z]+\s+)*(\b[\d]+[a-zA-Z]*\b)+$/