如何在Jquery中以给定的任何特定排序顺序对字符串数组进行排序

Question

I have and array of strings:

var arrStr = ["Ron", "Jhon", "Mary", "Alex", "Ben"];

The above array is the default sort order that I require. I have another array of Strings:

var arrStr2 = ["Mary", "Alex", "Jhon"];

I wanted to sort arrStr2 with the sort order in arrStr . (the order in arrStr also can be changed, accordingly the arrStr2 should be sorted). arrStr2 can have more values also, but the values will be only from any of the values in array arrStr

After sorting I need an out put for arrStr2 as ["Jhon","Mary","Alex"];

How can I achieve this using jQuery?

Answer 1

After sorting I need an out put for arrStr2 as ["Jhon","Mary","Alex"];

simply try this

arrStr2.sort(function(a,b){ return arrStr.indexOf(a) - arrStr.indexOf(b) });

Now arrStr2 will have the value you are expecting,

DEMO

 var arrStr = ["Ron", "Jhon", "Mary", "Alex", "Ben"]; var arrStr2 = ["Mary", "Alex", "Jhon"]; arrStr2.sort(function(a,b){ return arrStr.indexOf(a) - arrStr.indexOf(b) }); document.body.innerHTML = JSON.stringify( arrStr2, 0, 4 ); 

Answer 2

Just compute the intersection, no need to sort() :

 var arrStr = ["Ron", "Jhon", "Mary", "Alex", "Ben"]; var arrStr2 = ["Mary", "Alex", "Jhon"]; result = arrStr.filter(x => arrStr2.includes(x)) document.write('<pre>'+JSON.stringify(result,0,3)); 

(ES5 backporting left as an exercise).

Answer 3

This is one more approach:

var rank = {};
arrStr.forEach(function(e, i){rank[e] = i;});
arrStr2.sort(function(a, b) {return rank[a] - rank[b];});