[英]Matlab. Storing 2D arrays within 3D arrays
I have defined the following 2D function, 我定义了以下2D函数,
Ngrid = 100;
h = 1/(Ngrid-1);
x = 0:h:1;
y = 0:h:1;
[x y] = meshgrid(x,y);
f = exp(-((1-x).^2)./0.45)
and I want to store this function within the 3D array "c",along the "T" dimension, 我想将这个函数存储在3D数组“ c”中,以及“ T”维度中,
k = 0.001;
Tend = 1;
T = 0:k:Tend;
c = zeros(length(T),length(x),length(y));
What I have tried is, 我试过的是
c(1:end,:,:) = f;
but it does not work. 但它不起作用。 ¿Any idea of how can I store the same function within this 3D array? ¿关于如何在3D阵列中存储相同功能的任何想法?
Thanks in advance. 提前致谢。
The subscript dimension mismatch is because you are trying to squeeze 100 * 100
elements into a 1001 x 100 x 100
matrix. 下标尺寸不匹配是因为您试图将100 * 100
元素压缩到1001 x 100 x 100
矩阵中。
You could do this assignment the following way: 您可以通过以下方式进行此分配:
c(1,:,:) = f;
c(2,:,:) = f;
...
c(1001,:,:) = f;
But you can accomplish the same thing using repmat
但是您可以使用repmat
完成相同的操作
c = repmat(reshape(f, [1, size(f)]), [numel(T), 1 1]);
c = bsxfun(@plus, zeros(numel(T), 1), reshape(f, [1, size(f)]));
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.