我的php搜索代码出了点问题

Question

I am not sure what is going wrong with my code. 我不确定我的代码出了什么问题。 I am getting message "Page isn't working" not sure why ? 我收到消息“页面无法正常工作”，不确定为什么吗？ I am trying to fetch details of filter on "retrieve1.php" but each time i try to click on student filter i am getting a message saying "Page isn't working". 我试图在“ retrieve1.php”上获取过滤器的详细信息，但是每次我尝试单击学生过滤器时，我都会收到一条消息，指出“页面无法正常工作”。 I would appreciate any help here. 我会在这里对您有所帮助。

 <?php echo "<body style='background-color:#DCDCDC'>"; include ("account.php"); ( $db = mysql_connect( $hostname, $username, $password )) or die ( "unable to connect to MYSQL database" ); mysql_select_db( $project ); $sql= "SELECT * FROM bpi_registration LEFT JOIN bpi_schoolInfo on bpi_registration.id_school = bpi_schoolInfo.id_school"; $query=mysql_query($sql) or die(mysql_error()); function grade() { $query= "select distinct class_name from bpi_classInfo"; $result=mysql_query($query) or die(mysql_error()); while ($value = mysql_fetch_array ($result)) { echo "<option value='" . $value['class_name'] . "'>" . $value['class_name'] . "</option>"; } } function school() { $query= "select distinct school_name from bpi_schoolInfo"; $result=mysql_query($query)or die(mysql_error()); while ($value = mysql_fetch_array ($result)) { echo "<option value='" . $value['school_name'] . "'>" . $value['school_name'] . "</option>"; } } function team() { $query= "select distinct team_name from bpi_teamProfile"; $result=mysql_query($query)or die(mysql_error()); while ($value = mysql_fetch_array ($result)) { echo "<option value='" . $value['team_name'] . "'>" . $value['team_name'] . "</option>"; } } function students() { $query= "select * from bpi_registration"; $result=mysql_query($query)or die(mysql_error()); while ($value = mysql_fetch_array ($result)) { echo "<option value='" . $value['first_name'].' '.$value['last_name']. "'>" . $value['first_name'].' '.$value['last_name']. "</option>"; } } ?> <form action="retrieve1.php" method="GET"> <select name="Grade"> <option value="" selected="selected">Choose Grade</option> <?php grade() ?> </select> <select name="School"> <option value="" selected="selected">Choose School</option> <?php school() ?> </select> <select name="Team"> <option value="" selected="selected">Choose Team</option> <?php team() ?> </select> <select name="Students"> <option value="" selected="selected">Choose Students</option> <?php students() ?> </select> <input type="submit" value="Find" /> </form> <table width="600" border="2"> <tr> <th width="91"> <div align="center">First Name </div></th> <th width="98"> <div align="center">Last Name </div></th> <th width="198"> <div align="center">Email </div></th> <th width="97"> <div align="center">City </div></th> <th width="97"> <div align="center">State </div></th> <th width="59"> <div align="center">Country </div></th> <th width="59"> <div align="center">View </div></th> <tr> <?php if (isset($_GET['Students'])) { while ($row=mysql_fetch_array($query)) { echo $row['email']; echo $row['address_city']; echo $row['address_state']; echo $row['address_country']; } } ?>

Answer 1

You are writing a wrong code on select. 您在选择时编写了错误的代码。 Use the below one. 使用以下之一。

<form action="retrieve1.php" method="GET">

<select name="Grade">
<option value="" selected="selected">Choose Grade</option>
<?php grade() ?>
</select>

<select name="School">
<option value="" selected="selected">Choose School</option>
<?php school() ?>
</select>

<select name="Team">
<option value="" selected="selected">Choose Team</option>
<?php team() ?>
</select>

<select name="Students">
<option value="" selected="selected">Choose Students</option>
<?php students() ?>
</select>

<input type="submit" value="Find" />
</form>

and also you are missing curly brace end of while loop 而且您还缺少while循环的花括号结尾

<?php
if (isset($_GET['Students']))
{
    while ($row=mysql_fetch_array($query))
    {
        echo $row['email'];
        echo $row['address_city'];
        echo $row['address_state'];
        echo $row['address_country'];
    }
}
?>

Answer 2

You are missing } 您不见了}

<?php
if (isset($_GET['Students']))
{
    while ($row=mysql_fetch_array($query))
    {
        echo $row['email'];
        echo $row['address_city'];
        echo $row['address_state'];
        echo $row['address_country'];
    }
}
?>

我的php搜索代码出了点问题

问题描述

2 个解决方案

解决方案1
0 已采纳 2016-03-27 07:02:18

解决方案2
0 2016-03-27 07:03:23

我的php搜索代码出了点问题

问题描述

2 个解决方案

解决方案1 0 已采纳 2016-03-27 07:02:18

解决方案2 0 2016-03-27 07:03:23

解决方案1
0 已采纳 2016-03-27 07:02:18

解决方案2
0 2016-03-27 07:03:23