如何使用python使用文件参数启动参数化jenkins作业

Question

Scenario: I want to start a jenkins job with file parameters, using python to trigger the job.

Using

from jenkinsapi.jenkins import Jenkins

J = Jenkins('http://localhost:8080')

params = {'VERSION': '1.2.3', 'PYTHON_VER': '2.7'}

J.build_job('foo', params)

works for string parameters, but how do I use this if I need a file parameter?

Can anybody help me please?

Answer 1

Yes @markus-m you are right that with Build Parameter plugin you can build a job with file as a parameter.You can provide this file to browser and Jenkins will run your job accrodingly, However please find below my comments.

The file you are passing as an argument must be placed in your Jenkins workspace so that Jenkins can access and run this file. The same file name can also be accessed with Jenkins environment variables.

For your scenario, you have two solutions

1. Copy the file that you want to pass as parameter to Jenkins Workspace, so that when you run your job with file location, Jenkins will upload the file and Run accrodingly.

2. you can access Jenkins with Remote API's so that you can run CURL Command and pass file as parameter.