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Java中的抽象类-创建方法

[英]Abstract class in Java - creating methods

I have a question about abstract classes in Java. 我对Java中的抽象类有疑问。 I have created abstract class like this: 我创建了这样的抽象类:

public class userClass {
private String email;
String accountType;
account account;

public userClass(String email, String accountType){
    this.setEmail(email);
    this.setAccountType(accountType);

     if(accountType.equals("basic")){
          this.account = new basicAccount();
     } 
     else if(accountType.equals("premium")){
          this.account = new premiumAccount();
     }
}

As you see I have accounts of two types: basic and premium, they are both extensions of account abstract class. 如您所见,我有两种类型的帐户:基本帐户和高级帐户,它们都是帐户抽象类的扩展。 Now I would like to add method only to premium class, but when I'm trying to do so, I receive an error saying that I have to implement it in account class, which I don't want. 现在,我只想将方法添加到高级类中,但是当我尝试这样做时,我收到一条错误消息,说我必须在帐户类中实现它,这是我所不希望的。 Is it possible to do it in other way? 有可能以其他方式做到吗? To avoid putting empty method in account and basicAccount classes? 为了避免将空方法放在account和basicAccount类中?

So you if you have an Account class like: 因此,如果您有一个Account类,例如:

public abstract class Account{
    public abstract void doSomethingAccountLike();
    //more stuff
}

You can have child classes: 您可以有子班:

public class BasicAccount extends Account{
    public void doSomethingAccountLike(){
        //implementation specific to basic accounts
    }
}

public class PremiumAccount extends Account{
    public void doSomethingAccountLike(){
        //implementation specific to premium accounts
    }

    public void doSomethingPremiumLike(){
        //something that only makes sense
        // in the context of a premium account
    }
}

The method doSomethingPremiumLike() is only available when you have an instance of a PremiumAccount ie: doSomethingPremiumLike()方法仅在拥有PremiumAccount实例的情况下PremiumAccount即:

public class AccountDemo{
    public static void main(String[] args){
        PremiumAccount premium = new PremiumAccount();
        BasicAccount basic = new BasicAccount();
        Account generalAccount = premium;

        //valid- the compiler knows that the
        //premium object is an instance of the
        //premium class
        premium.doSomethingPremiumLike();

        //Would cause a compile error if uncommented.
        //The compiler knows that basic is an instance
        //of a BasicAccount, for which the method
        //doSomethingPremiumLike() is undefined.
        //basic.doSomethingPremiumLike();

        //Would generate a compiler error if uncommented.
        //Even though generalAccount actually refers to
        //an object which is specifically a PremiumAccount,
        //the compiler only knows that it has a reference to
        //an Account object, it doesn't know that it's actually
        //specifically a PremiumAccount. Since the method
        // doSomethingPremiumLike() is not defined for a general
        //Account, this won't compile
        //generalAccount.doSomethingPremiumLike();

        //All compile- all are instances of Account
        //objects, and the method doSomethingAccountLike()
        //is defined for all accounts.
        basic.doSomethingAccountLike();
        premium.doSomethingAccountLike();
        generalAccount.doSomethingAccountLike();
    }
}

Your issue 你的问题

It sounds to me like your issue is likely that in the class UserClass , you have a field Account account . 在我看来,您的问题很可能是在UserClass类中,您有一个字段Account account In your constructor, you assign either a new BasicAccount() or a new PremiumAccount() to the field account . 在构造函数中,您可以将new BasicAccount()new PremiumAccount()分配给字段account This is perfectly fine, but once you do that, the compiler no longer knows in any given case whether the account field refers to a PremiumAccount instance or a BasicInstance . 这样做很好,但是一旦执行此操作, 编译器就不再在任何给定情况下都知道account字段是引用PremiumAccount实例还是BasicInstance This means that if you try to call account.doSomethingPremiumLike() , you will get a compiler error. 这意味着,如果您尝试调用account.doSomethingPremiumLike() ,则会收到编译器错误。 You can get around this restriction at runtime: 您可以在运行时解决此限制:

In UserClass somewhere: UserClass某处:

if(account instanceof PremiumAccount){
    //if we're sure that account is actually a PremiumAccount,
    //cast it to a PremiumAccount here to let the compiler know
    //that doSomethingPremiumLike() can be called 
   ((PremiumAccount)account).doSomethingPremiumLike();
}

Note: I have changed the names of your classes to start with upper case letters as is the common convention in Java and most other OOP languages. 注意:我已经将类的名称更改为以大写字母开头,这是Java和大多数其他OOP语言中的常见约定。 It's good to get in the habit of following this convention to help others read your code. 养成遵循此约定以帮助他人阅读您的代码的习惯是很好的。

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