[英]Regex for route matching in PHP
I am working on my mini url router in PHP. 我正在用PHP开发迷你网址路由器。 So far I've got regex for extracting variables in the url enclosed in {}(By looking at Symfony's router code) : 到目前为止,我已经获得了正则表达式,用于提取{}中的网址中的变量(通过查看Symfony的路由器代码):
public function parse($pattern)
{
$matches = '';
$variables = array();
$pos = 0;
preg_match_all('#\{\w+\}#', $pattern, $matches, PREG_OFFSET_CAPTURE | PREG_SET_ORDER);
foreach ($matches as $match)
{
$varName = substr($match[0][0], 1, -1);
if(is_numeric($varName)) {
throw new Exception('Argument cannot be a number');
}
if (in_array($varName, $variables)) {
throw new \LogicException(sprintf('More then one occurrence of variable name "%s".', $varName));
}
$variables[] = $varName;
}
return ['variables' => $variables];
}
So this method extracts the vars, now I need a regex to match the pattern of the route with the url. 因此,此方法提取了var,现在我需要一个正则表达式来匹配带有url的路由模式。 I started learning about regexes, but I still am not that good to wrap my head around this. 我开始学习有关正则表达式的知识,但我仍然不愿意为此做任何事情。
This will work: \\/hello\\/{?([^\\/}]+)}?
这将起作用: \\/hello\\/{?([^\\/}]+)}?
(At least it does on the examples you provided:) (至少在您提供的示例中如此:)
/hello/{name} /hello/Sam
\\/
is an escaped /
\\/
是一个转义的/
hello
finds hello
, in case you didn't realize. hello
发现hello
,以防万一你没有意识到。 {?
finds a {
, if there is one. 找到{
,如果有一个。 ([^\\/}]+)
finds everything that's not a /
or }
([^\\/}]+)
查找不是/
或}
}?
finds a }
, if there is one. 找到一个}
,如果有的话。 For anyone that might be interested, I got it, thanks to Laurel's answer. 对于任何可能感兴趣的人,我都感谢劳雷尔的回答。
This is the updated version of the method it still needs some work though : 这是该方法的更新版本,但仍然需要一些工作:
$matches = '';
$variables = array();
$pos = 0;
$reg = '#';
$nextText = '';
preg_match_all('#\{\w+\}#', $pattern, $matches, PREG_OFFSET_CAPTURE | PREG_SET_ORDER);
foreach ($matches as $match)
{
$varName = substr($match[0][0], 1, -1);
$precedingText = substr($pattern, $pos, $match[0][1] - $pos);
$pos = $match[0][1] + strlen($match[0][0]);
$nxt = $pos - strlen($pattern);
if($nxt == 0) $nxt = strlen($pattern);
$nextText = substr($pattern, $nxt);
//$precedingText = substr($precedingText, 1, -1);
$precSegments = explode('/', $precedingText);
$precSegments = array_splice($precSegments, 1);
//$temp = 5;
echo 'nxt ' . $nextText . '<><br>';
if(strlen($precedingText) > 1)
{
foreach($precSegments as $key => $value)
{
$reg .= '\/';
$reg .= $value;
}
$reg .= '{?([^\/}]+)}?';
}
else
{
$reg .= '{?([^\/}]+)}?';
}
$nextText = str_replace('/', '\/', $nextText);
if(is_numeric($varName)) {
throw new Exception('Argument cannot be a number');
}
if (in_array($varName, $variables)) {
throw new \LogicException(sprintf('More then one occurrence of variable name "%s".', $varName));
}
$variables[] = $varName;
}
if(count($matches) < 1)
{
$reg .= str_replace('/', '\/', $pattern);
}
$reg = $reg . $nextText;
$reg .= '#';
if($pattern == '/')
{
$reg = '#^[\/]+$#';
}
return ['variables' => $variables, 'regex' => $reg];
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.