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Kotlin:如何延迟初始化向量

[英]Kotlin: How to Lazy Initialization a Vector

When I lazy initialise a vector. 当我懒惰初始化向量时。 I could do it for normal Object class as below. 我可以为普通的Object类做到这一点,如下所示。

val mPagerAdapter: PagerAdapter by lazy {
    PagerAdapter(supportFragmentManager, fragments, mTabsName)
}

However, when I lazy initialise a Vector variable as below 但是,当我懒惰初始化如下的Vector变量时

val fragments = Vector<Fragment>() by lazy {
    Vector<Fragment>()
}

It gave me error stating Unresolve Reference: by . 它给我指出了Unresolve Reference: by错误。 How to fix this problem that I could lazy initialise it? 如何解决这个我可能会懒惰初始化的问题?

在第二种情况下,语法与第一个摘要明显不同(您可以在by之前初始化变量),请比较:

val fragments by lazy { Vector<Fragment>() }

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