在matplotlib中设置默认散点图标记

Question

I'm looking for a way to set the default marker for plt.scatter() - I've tried setting this line in my matplotlibrc file:

lines.marker    : +

but this doesn't appear to change the default marker, which is a circle.

http://matplotlib.org/users/customizing.html doesn't seem to have any other obvious parameter to set either; does anyone know if it is actually possible to set the default marker for a scatter plot?

Answer 1

You can do this by changing directly the code in site-packages/matplotlib/pyplot.py :

# This function was autogenerated by boilerplate.py.  Do not edit as
# changes will be lost
@_autogen_docstring(Axes.scatter)
def scatter(x, y, s=20, c=None, marker='+', cmap=None, norm=None, vmin=None,
            vmax=None, alpha=None, linewidths=None, verts=None, edgecolors=None,
            hold=None, data=None, **kwargs):
    ax = gca()
    # allow callers to override the hold state by passing hold=True|False
    washold = ax.ishold()

Mind the warning in the comment since I'm not sure when boilerplate.py is being called. (You just need to try it out and see) However before actually changing the source consider overlapping plt.scatter with your own call:

import matplotlib.pyplot as plt
import numpy as np

class scatter():
    def __init__(self,x,y):
        self.marker = '+'
        plt.scatter(x,y,marker=self.marker)

x,y = np.random.randint(0,100,30),np.random.randint(0,100,30)
scatter(x,y)
plt.show()