Matplotlib scatter()：大小、标记形状的默认值

Question

Is there a way to set default marker size ( s ) parameter for matplotlib plt.scatter() (or likewise to set the shape of the marker)?

mpl.rcParams.keys() has settings for the line plots, eg

import matplotlib as mpl
mpl.rcParams['lines.marker']='D'

... but they do not seem to relate to plt.scatter() .

Thanks.

Clarification:

I'd like to use a configuration mechanism like mpl.rcParams() , or some other reasonably civilized method. Locally modifying library code is not it.

On the other hand, if it cannot currently be done and somebody submits a patch to Matplotlib, that would be awesome.

Answer 1

Of course there is, it's all in the pyplot.py

A snippet from their code:

def scatter(x, y, s=20, c=None, marker='o', cmap=None, norm=None, vmin=None,
            vmax=None, alpha=None, linewidths=None, verts=None, edgecolors=None,
            hold=None, data=None, **kwargs):

The size is set to 20 s=20 and the marker shape is a circle marker='o' which agrees with their documentation

Answer 2

In the current release, marker size is defined as:

"The marker size in points**2. Default is rcParams['lines.markersize'] ** 2."

So setting rcParams['lines.markersize'] should change the default marker size for scatterplots too now. See https://matplotlib.org/stable/api/_as_gen/matplotlib.pyplot.scatter.html

Answer 3

It is not possible in the current release of matplotlib ( http://matplotlib.org/users/customizing.html ).

However, there is an option to change the default marker in the master branch on GitHub ( https://github.com/matplotlib/matplotlib/blob/master/lib/matplotlib/rcsetup.py#L1112 ).