用 sed 替换最后一次出现的空格

Question

I need to replace the last occurrence of space in an input file, using sed .

What I came up with is

sed "s/([ ])[0-9]*$/,/g"

However, it does not seem to want to remember the space which it's supposed to replace. Running the command without round brackets works fine (for what it's supposed to do - replace the space and the chain of numbers). When I add the brackets, it does nothing.

Yes, I am aware of this solution, however when trying to pass \\1 to sed , it screams that "\\1 not defined in the RE".

Anyone care to help? It seems to be a simple issue, I'd be glad to know the solution.

Answer 1

这似乎“第一次”起作用（是的）......

$ sed -e 's/ \([^ ][^ ]*\)$/,\1/' /etc/hosts