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在java中获取7-Zip信息

[英]Getting 7-Zip information in java

I'm using 7-zip in my java program to zip several files and folders (mostly games) to several 7-zip files.我在我的 java 程序中使用 7-zip 将几个文件和文件夹(主要是游戏)压缩到几个 7-zip 文件中。

As an example:举个例子:

test1.txt and test1 -> test1.7z
test2.txt and test2 -> test2.7z

The zipping is no problem, but since the folders can be really large I wanted to include 2 progress bars (so the user can check how far the zip-process is).压缩没有问题,但由于文件夹可能非常大,我想包括 2 个进度条(以便用户可以检查压缩过程有多远)。

Currently I have the following code (which works so far), but how can I get the percentage of the zipping process?目前我有以下代码(到目前为止有效),但是如何获得压缩过程的百分比? The current output just gives back the start and result of the zipping process.当前输出只返回压缩过程的开始和结果。

private void runZipCommand() {
    ProcessBuilder pb = null;

    ArrayList<Game> game = getGames();

    for (Game g : game) {
        pb = new ProcessBuilder(makeZipString(g, false));
        pb.redirectError();
        try {
            Process p = pb.start();

            InputStream is = p.getInputStream();
            InputStreamReader isr = new InputStreamReader(is);
            BufferedReader br = new BufferedReader(isr);
            String line;

            while((line = br.readLine()) !=null){
                System.out.println(line);
            }               

            System.out.println("Exited with: " + p.waitFor());
        } catch (Exception ex) {
            ex.printStackTrace();
        }
    }

}

private String makeZipString(Game g, boolean batch) {
    String programzip = "";
    String gametitle = "";
    String restfiles = "";
    programzip = "\"" + sevenPath + "\\7z.exe\" " + ZIPCOMMANDS;

    if (batch) {
        gametitle = " \"" + g.getName().replaceAll("[_[^\\w\\däüöÄÜÖ\\+\\- ]]", "") + ".7z\" ";
    } else {
        gametitle = " \"" + backupPath.toString() + "\\" + g.getName().replaceAll("[_[^\\w\\däüöÄÜÖ\\+\\- ]]", "")
                + ".7z\" ";
    }

    restfiles = "\"" + g.getAppmanifest() + "\" \"" + steamUtil.getInstallDir() + "\\" + g.getDir() + "\"";

    String s = programzip + gametitle + restfiles;

    return s;
}

Is there any way to get the percentage of how far the single process (zipping test1.7z) is?有没有办法获得单个进程(压缩 test1.7z)的百分比?

If you need more information, I try to add it as fast as possible.如果您需要更多信息,我会尽量尽快添加。

Thanks for your answers.感谢您的回答。

LevKaz列夫卡兹

I think I solved my problem now.我想我现在解决了我的问题。

My "old" zip-command had following commands and switches:我的“旧”zip 命令具有以下命令和开关:

7z.exe a -t7z -m0=LZMA2 -mx9 -mmt=2

After checking out the 7-zip.chm, I found out, that I can change the output stream via switch:在查看 7-zip.chm 后,我发现我可以通过 switch 更改输出流:

-bs

After changing the output streams to the following将输出流更改为以下内容后

7z.exe a -t7z -m0=LZMA2 -mx9 -mmt=2 -bso0 -bse2 -bsp1

I can extract the progress from my BufferedReader.我可以从我的 BufferedReader 中提取进度。

Anyway, thanks to all who visited my question and special thanks to @DavidS for linking in the other question which led me to the right point.无论如何,感谢所有访问我的问题的人,并特别感谢@DavidS 链接到另一个问题,这让我找到了正确的观点。

EDIT:编辑:

This also is going well while extracting a *.7z file.这在提取 *.7z 文件时也很顺利。 Use the following command:使用以下命令:

7z.exe x -bso0 -bse2 -bsp1 archive.7z -aoa -o"c:\OutputPath"

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