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React如何调用ES6类的render函数,使`this`不引用类本身?

[英]How does React call the render function of an ES6 class in a such a way that `this` does not refer to the class itself?

For example, given the class with a function increaseQty 例如,给定具有函数increaseQty的类

increaseQty() {
  this.qty++
}

and the call 和电话

render() {
  return (
    <div>
      <button onClick={this.increaseQty}>Increase</button>
    </div>
  )
}

this.qty will be undefined unless I write a line in my constructor binding the context of this in the constructor to the function this.qty是不确定的,除非我写我的构造线结合的情况下this在构造函数中的作用

constructor(props) {
  super(props)
  this.qty = 0
  this.increaseQty = this.increaseQty.bind(this) // <---- like so
}

However this isn't the case in a normal es6 class if you're just using it normally: 但是,如果您只是正常使用它,那么在正常的es6类中就不是这种情况:

https://jsfiddle.net/omrf0t20/2/ https://jsfiddle.net/omrf0t20/2/

class Test {
  constructor() {
    this.qty = 0
  }

  increaseQty() {
    console.log(++this.qty)
  }

  doStuff() {
    this.increaseQty()
  }
}

const t = new Test()
t.doStuff() // prints 1

What aspect of React makes it so that render is called without the context of this ? 哪些方面发生反应使得它使render调用时没有的情况下this

The difference here is that in your example with React you are passing increaseQty as a callback to another component, but in the second, you are calling it within the current context. 这里的区别是,在你的榜样与之反应你逝去的increaseQty作为回调到另一个组件,但在第二,你是在当前上下文中调用它。

You can see the difference here in simplified example 您可以在简化示例中看到差异

class Test {
  constructor() {
    this.qty = 0
  }

  increaseQty() {
    console.log(++this.qty)
  }

  doStuff() {
    this.increaseQty(); // no need to bind
  }

  listenClicks() {
    // you should use bind to preserve context
    document.body.addEventListener('click', this.increaseQty.bind(this)); 
  }
}

React guidelines also recommend you bind methods in the constructor, to make the code more optimal, bind it once and always use the same function rather than create a new bound version for each render() call. React指南还建议您在构造函数中绑定方法,使代码更加优化,绑定一次并始终使用相同的函数,而不是为每个render()调用创建新的绑定版本。

This isn't really an ES6 specific question (other than the fact that we are referencing a class and constructor). 这不是一个特定于ES6的问题(除了我们引用类和构造函数之外)。 What you're doing in your function is just incrementing a value. 你在函数中所做的只是递增一个值。 If that value has not been initialized to something (even in ES5) then it will throw an error. 如果该值尚未初始化为某些内容(即使在ES5中),则会引发错误。 You can't add 1 to undefined . 您不能将1添加到undefined

In ES5 (and ES6 really) this would be a problem: 在ES5(和ES6真的)这将是一个问题:

var myObj = {
    addOne: function() {
        this.qty++;
    }
}

myObj.addOne(); // Error! this.qty is undefined

Whereas this would resolve it: 虽然这会解决它:

var myObj = {
    qty: 0,
    addOne: function() {
        this.qty++;
    }
}

myObj.addOne(); // Good to go

It's the same situation in your class. 你班上的情况也是如此。 You cannot increment a variable that you haven't declared and initialized to a number value. 您不能将尚未声明和初始化的变量增加到数值。

In an even simpler example this: 在一个更简单的例子中:

var x;

x++;

would throw an error whereas this: 会抛出一个错误,而这个:

var x = 0;

x++;

is good. 很好。

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