[英]Search common characters in strings and return pointer to the common character (without using strpbrk)
Following code finds the common character in two strings and returns a pointer to the common string if any. 以下代码在两个字符串中查找公共字符,并返回指向公共字符串(如果有)的指针。 I'm trying to emulate the function strpbrk without using any builtin functions or subscripts.
我试图在不使用任何内置函数或下标的情况下模拟strpbrk函数。
#include <stdio.h>
#include <stdlib.h>
char *find_char( char const *source, char const *chars ){
char* str1;
char* str2;
if (source == NULL || chars == NULL)
return NULL;
else {
for( *str1=&source != '\0'; ++str1;){
for( *str2=&chars != '\0'; ++str2;){
if (*str1 == *str2)
return str1;
else return NULL;}
}
}
}
char* main(){
char const *source = "ab";
char const *chars = "bc";
find_char(source, chars);
}
But I'm getting the following error 但我收到以下错误
Running "/home/ubuntu/workspace/hello-c-world.c"
运行“ /home/ubuntu/workspace/hello-c-world.c”
bash: line 12: 29755 Segmentation fault "$file.o" $argsbash:第12行:29755分段错误“ $ file.o” $ args
Process exited with code: 139进程退出,代码为:139
I am a beginner at C and learning how to manipulate pointers, please let me know what am I doing wrong and how I can strengthen my C programming skills, right now I'm mostly using Kenneth Reek's book "Pointers on C" 我是C的初学者,正在学习如何操作指针,请让我知道我在做错什么以及如何增强C编程技能,现在我主要使用Kenneth Reek的书“ C上的指针”
Thanks 谢谢
Various ìf
logic and runaway pointer problems. 各种
ìf
逻辑和失控指针的问题。 Fixed code below: 固定代码如下:
char *find_char( char const *source, char const *chars ){
char* str1;
char* str2;
if (source != NULL && chars != NULL) {
for( str1=source; *str1; str1++){
for( str2=chars; *str2; str2++){
if (*str1 == *str2) return str1;
}
}
}
return NULL;
}
char* main(){
char const *source = "ab";
char const *chars = "bc";
char *x;
x = find_char(source, chars);
if (x != NULL) printf("%c", *x);
}
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