带有strpbrk的c中的字符和字符串

Question

Given the followings :

char delimiters1[] = {' ' , '&' , '<' , '>'};


char delimiters2[] =  " &<>";

If I use the C function strpbrk with delimiters1 and delimiters2 , the results would be the same ?

I've tested both of them with something like 20 inputs , and I got the same output for both .

Am I wrong ?

thanks .

Answer 1

char delimiters1[] = {' ' , '&' , '<' , '>'};

should be:

char delimiters1[] = {' ' , '&' , '<' , '>', 0};

It may work few times. But sting should be null-terminated. Otherwise, how will strpbrk will know the end of chars to be searched?

This is the snippet of strbrk() :

  while (*s1)
    {
      for (c = s2; *c; c++)
    {
      if (*s1 == *c)
        break;
    }
      if (*c)
    break;
      s1++;
    }

Where c is the pointer to the char-set. As you can clearly see that at some point *c should be null for the program to work correctly.