strpbrk函数 - C.

Question

I am trying to break a string from the occurrence of the given character. I am using the strpbrk function. But I get this error

21 G:\My Programs\C\horse.cpp invalid conversion from `char' to `const char*' 

The code which I used is as follows

char horses[100], h[1];

 char *brokenstring;

 h[0] = 'H';

 brokenstring = strpbrk (horses,h[0]);

I get this error in the line where I use the strpbrk function. Please help me out.

Answer 1

You need to pass a const char * to strpbrk()'s 2nd argument and also you need to terminate the string with null.

int main( int argc, char ** argv ) {    

 char horses[100], h[2];
 char *brokenstring;

 h[0] = 'H';
 h[1]=0;   
 brokenstring = strpbrk (horses,h);
 return 0;
}

Answer 2

The second argument to strpbrk must be a string, not a char.

It is not clear what you want to do; are you sure you don't need, eg, strtok()?

strpbrk() is useful if you have several possible dividing characters (eg H, Y and K -- then you pass "HYK"). Otherwise you'll be better served by strchr().

Answer 3

You passed the second argument of strpbrk a char, not a pointer to chars.

You need to call strpbrk (horses, h)

Answer 4

Looking at http://www.cplusplus.com/reference/clibrary/cstring/strpbrk/ I see that the function looks like this

char * strpbrk ( const char *, const char * ); 

But you are passing it horses and h[0] . h[0] is not a char * , it is actually a char . If you just passed it h you would be OK.

Edit: as others have said, you actually would need to make sure you null terminated h.