[英]Arrays and strpbrk in C
If my array is : 如果我的数组是:
char* String_Buffer = "Hi my name is <&1> and i have <&2> years old."
char* pos = strpbrk(String_buffer, "<");
Now pos is : 现在pos是:
" <&1> and i have <&2> years old. "
“ <&1>并且我已经<&2>岁。”
But i need "Hi my name is". 但是我需要“嗨,我叫”。 How can do this?
怎么办
First, make sure that the string you are working with is in modifiable memory 1 : 首先,请确保您正在使用的字符串在可修改的内存1中 :
char String_Buffer[] = "Hi my name is <&1> and i have <&2> years old."
then, cut your string at the position where you found <
: 然后,在找到
<
的位置剪切字符串:
char* pos = strpbrk(String_buffer, "<");
if(pos!=NULL)
{
/* changing the '<' you found to the null character you are actually
* cutting the string in that place */
*pos=0;
}
Printing String_Buffer
will now output Hi my name is
. 打印
String_Buffer
现在将输出Hi my name is
。 If you don't want the final space, just move pos
backward of one element (being careful not to go before the beginning of String_Buffer
). 如果您不想要最后一个空格,只需将
pos
向后移一个元素(注意不要移到String_Buffer
的开头)。
char
pointer and made it point to a string literal, which is non-modifiable (that's why you normally write const
char * str = "asdasads";
; in this case, instead, we are initializing a local char
array, which we can change as much as we want. char
指针,并将其指向不可修改的字符串文字(这就是您通常编写const
char * str = "asdasads";
;在这种情况下,我们正在初始化本地char
数组,我们可以根据需要进行任意更改。 If you track start
separately, you can "cut out" a section of the buffer: 如果单独跟踪
start
,则可以“剪切”缓冲区的一部分:
char *start = String_Buffer;
char *end = strpbrk(String_Buffer, "<");
if (end) {
/* found it, allocate enough space for it and NUL */
char *match = malloc(end - start + 1);
/* copy and NUL terminate */
strncpy(match, start, end - start);
match[end - start] = '\0';
printf("Previous tokens: %s\n", match);
free(match);
} else {
/* no match */
}
To walk the buffer printing each token, you'll simply hoist this into a loop: 要遍历打印每个令牌的缓冲区,只需将其提升为循环:
char *start = String_Buffer, *end, *match;
while (start) {
end = strpbrk(start, "<");
if (!end) {
printf("Last tokens: %s\n", start);
break;
} else if (end - start) {
match = malloc(end - start + 1);
/* copy and NUL terminate */
strncpy(match, start, end - start);
match[end - start] = '\0';
printf("Tokens: %s\n", match);
free(match);
end++; /* walk past < */
}
/* Walk to > */
start = strpbrk(end, ">");
if (start) {
match = malloc(start - end + 1); /* start > end */
strncpy(match, end, start - end);
match[start - end] = '\0';
printf("Bracketed expression: %s\n", match);
free(match);
start++; /* walk past > */
}
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.