如何在window.open中打开一个按钮查看视图，并在angularJs中作为弹出窗口打开

Question

Basically I am new in angularJs do not know what approach to be follow in opening a View in a popup window on button click. I am using hybrid application angular js with MVC. Not using routing concept in angularJs. Can anyone help me.

Answer 1

You can use the $modal service of angularJS and pass you view as template;

  $modal.open({
    template: Template,       
    size: 'md'
  });