[英]Using an sql query result as a search term for a new sql statement
So I am trying to use a result from an SQL search $search_course
and then having that as the WHERE LIKE
part of the next statement $Search_Module
.所以我试图使用 SQL 搜索
$search_course
,然后将其作为下一个语句$Search_Module
的WHERE LIKE
部分。
once the $Search_Module
query has finished I would like the results to be in a list which I know should be coded correctly.一旦
$Search_Module
查询完成,我希望结果出现在我知道应该正确编码的列表中。
I have tried the following code but the search returns no values;我尝试了以下代码,但搜索没有返回任何值;
Any help with this would be much appreciated, thanks in advance.任何与此有关的帮助将不胜感激,在此先感谢。
$search_course = "
SELECT title, id, wyl, overview, module, course, careers
FROM course
LEFT JOIN cm
ON course.id=cm.course
WHERE id LIKE '%".$_POST['submitcourseselection']."%'";
$result = $mysqli->query($search_course) or die($mysqli->error);
$display_course = $result->fetch_assoc();
//Searches the module table in the DB for modules within the course
$Search_Module = "
SELECT id, title, level, credits
FROM module
WHERE id LIKE '".$search_course['module']."'";
$M_Results = $mysqli->query($Search_Module) or die($mysqli->error);
$ModuleList = '';
while ($MResults = $M_Results->fetch_assoc()) {
$ID = $MResults['id'];
$Title = $MResults['title'];
$Level = $MResults['level'];
$Credits = $MResults['credits'];
$ModuleList.='<div><h2>'.$Title.'</h2></div>';
}
you don't need LIKE in your second query and you can do all by one query.您在第二个查询中不需要 LIKE,您可以通过一个查询完成所有操作。
$search_course = "
SELECT id, title, level, credits
FROM module
WHERE id IN (SELECT module
FROM course
LEFT JOIN cm
ON course.id=cm.course
WHERE id LIKE '%".$_POST['submitcourseselection']."%'")";
in your where clause WHERE id LIKE '".$search_course['module']."'";
, you are referencing an array location of a string $search_course
, which is your SQL statement.在您的 where 子句
WHERE id LIKE '".$search_course['module']."'";
,您正在引用字符串$search_course
的数组位置,这是您的 SQL 语句。
I think you meant to reference your result array $display_course
, so try this:我想你的意思是引用你的结果数组
$display_course
,所以试试这个:
$search_course = "
SELECT title, id, wyl, overview, module, course, careers
FROM course
LEFT JOIN cm
ON course.id=cm.course
WHERE id LIKE '%".$_POST['submitcourseselection']."%'";
$result = $mysqli->query($search_course) or die($mysqli->error);
$display_course = $result->fetch_assoc();
//Searches the module table in the DB for modules within the course
$Search_Module = "
SELECT id, title, level, credits
FROM module
WHERE id LIKE '".$display_course['module']."'";
$M_Results = $mysqli->query($Search_Module) or die($mysqli->error);
$ModuleList = '';
while ($MResults = $M_Results->fetch_assoc()) {
$ID = $MResults['id'];
$Title = $MResults['title'];
$Level = $MResults['level'];
$Credits = $MResults['credits'];
$ModuleList.='<div><h2>'.$Title.'</h2></div>';
}
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