如何在asmjit中获取当前指令？

Question

According to this post , in x64, you can perform lea rax, [rip] to get the current instruction. How would I do this using asmjit?

Answer 1

我想出了解决方案： assembler.lea(asmjit::x86::rax, asmjit::x86::ptr(asmjit::x86::rip));