将十六进制值的列表/字符串解包为整数

Question

I'm trying to unapck a list from hex to integers in python.

So for example:

hexValues = '\x90\x82|uj\x82ix'
decodedHex = struct.unpack_from('B', hexValues,0)
print decodedHex

Which would print (144,) and nothing else. Is there any way I can loop through this string to get all values? (bear in mind the length of hex values is much longer than the example given.)

Answer 1

You can get all the values at once:

import struct

hexValues = '\x90\x82|uj\x82ix'
format = '%dB' % len(hexValues)
decodedHex = struct.unpack_from(format, hexValues)
print(decodedHex)  # -> (144, 130, 124, 117, 106, 130, 105, 120)

As Jon Clements helpfully pointed out in a comment, you don't really need to use the struct module:

decodedHex = tuple(bytearray(hexValues))
print(decodedHex)  # -> (144, 130, 124, 117, 106, 130, 105, 120)