Python将三个整数转换为十六进制字符串

Question

I'm using python to control a mouse, for that I need to convert 3 integers to a hex value like b'\\x00\\x64\\x64'

What I've tried

return b'\x00' + hex(x) + hex(y)

But my IDE doesn't like this syntax, am I missing anything?

Answer 1

The simplest is probably to use the struct module:

import struct

def f(x, y):
    return struct.pack('bbb', 0, x, y)

Another way to do it without struct :

def byte_to_bytestr(x):
    return x.to_bytes(1, byteorder='big')

def f(x, y):
    return b''.join(map(byte_to_bytestr, [0, x, y]))

Answer 2

x = 100
y = 100

print(bytes("\x00\{}\{}".format(hex(x), hex(y)), 'utf-8'))

That should do the trick