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从函数 C++ 返回结构数组

[英]Return struct array from function c++

i am trying pass a struct array from a function.我正在尝试从函数传递一个结构数组。 i searched a lot but was unable to find a way to this.我搜索了很多,但无法找到解决此问题的方法。 below is the code i am tring.下面是我正在尝试的代码。

struct menuItemType
{
    int itemNo;
    string menuItem;
    double price;
};

void getData(menuItemType *menuList[10])
{
    menuList[0]->itemNo = 111;  
    menuList[0]->menuItem = "Apple";    
    menuList[0]->price = 2.00;

    ....
    menuList[0]->itemNo = 120;  
    menuList[0]->menuItem = "Chocolate";    
    menuList[0]->price = 5.00;
}

int main()
{
    /* i know that i can't return a array. but i want to get the menuList[10] values here. 
    not sure which code i have to use..*/
}

Your void getData(menuItemType *menuList[10]) does not return anything.您的void getData(menuItemType *menuList[10])不返回任何内容。 Instead, it fills the data in the memory pointed by input parameter.相反,它填充输入参数指向的内存中的数据。

int main()
{
    menuItemType data[10];
    getData(&data);
    std::cout << data[9].menuItem << std::endl; // Chocolate
}

However, why are you insisting on using low level arrays?但是,您为什么坚持使用低级数组? Use std::vector instead.改用std::vector

std::vector<menuItemType> getData()
{
    std::vector<menuItemType> data;
    data.push_back({111, "Apple", 2.00});
    ...
    data.push_back({120, "Chocolate", 5.00});
    return std::move(data);
}

int main()
{
    std::vector<menuItemType> data = getData();
    std::cout << data[9].menuItem << std::endl; // Chocolate
}

It will print Chocolate , because I assume there is a typo in your code.它将打印Chocolate ,因为我认为您的代码中有错字。

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