[英]Javascript join two json and compare
I have this code: 我有以下代码:
var json = '[{"id":113,"price":55,"start":"Sun, 24 Apr 2016 00:00:00 +0000","user_id":8},{"title":"","start":"2016-04-25T23:00:00.000Z","price":"115.7"},{"title":"","start":"2016-05-06T23:00:00.000Z","price":"115.7"},{"id":114,"price":45,"start":"Sun, 08 May 2016 00:00:00 +0000","user_id":9},{"title":"","start":"2016-05-08T23:00:00.000Z","price":"115.7"},{"id":111,"price":55,"start":"Wed, 01 Jun 2016 00:00:00 +0000","user_id":11},{"title":"","start":"2016-06-01T23:00:00.000Z","price":"115.7"},{"id":110,"price":53,"start":"Fri, 03 Jun 2016 00:00:00 +0000","user_id":8}]';
moment.utc().valueOf();
function fulljson(data) {
data = jQuery.parseJSON(data);
start = moment.utc('Sun, 24 Apr 2016 00:00:00 +0000').valueOf()/86400000;
start = parseInt(start);
console.log('pocetak'+start);
now = moment.utc().valueOf()/86400000;
now = parseInt(now);
console.log('sada'+now);
end = moment.utc('Sun, 05 Jun 2016 00:00:00 +0000').valueOf()/86400000;
end = parseInt(end);
console.log('kraj'+end);
auction_end = parseInt('3');
now = now + auction_end;
console.log('a sada je '+now);
if (start > now) {
pocetak = start;
console.log(pocetak);
} else {
pocetak = now;
console.log(pocetak);
}
var array_of_all_dates = [];
for (i = pocetak; i < end; i++) {
var new_object = {
title: '1',
start: moment(i*86400000).utcOffset('+0000').format(),
price: '{{$article->lowest_bid}}'
};
array_of_all_dates.push(new_object);
}
document.write(JSON.stringify(array_of_all_dates));
console.log(array_of_all_dates);
};
fulljson(json);
so at the end you see that I have json
and array_of_all_dates
. 所以最后您会看到我有json
和array_of_all_dates
。 Now I want to join json
to array_of_all_dates
but if the same start
element already excist into array_of_all_dates
then remove it from array_of_all_dates and put this from json
... 现在,我想加入 json
到array_of_all_dates
但如果同样的start
元素已经excist到array_of_all_dates
然后从array_of_all_dates删除它,然后把这个从json
...
http://jsbin.com/qekijumobe/edit?html,js,output http://jsbin.com/qekijumobe/edit?html,js,输出
How to do this? 这个怎么做? please help. 请帮忙。
As far as I understand and interpret your question 据我了解并解释您的问题
Json is 杰森是
[
{
"id":113,
"price":55,
"start":"Sun, 24 Apr 2016 00:00:00 +0000",
"user_id":8
},
{
"title":"",
"start":"2016-04-25T23:00:00.000Z",
"price":"115.7"
},
{
"title":"",
"start":"2016-05-06T23:00:00.000Z",
"price":"115.7"
},
..
}
And array_of_all_dates is 并且array_of_all_dates是
[
{
"title":"1",
"start":"2016-04-24T00:00:00+00:00",
"day":16915,
"price":100
},
{
"title":"1",
"start":"2016-04-25T00:00:00+00:00",
"day":16916,
"price":100
},
{
"title":"1",
"start":"2016-04-26T00:00:00+00:00",
"day":16917,
"price":100
},
...
}
So you need to join these two, without having a duplicate "start" field. 因此,您需要将这两者结合在一起,而不必使用重复的“开始”字段。 My approach would be too merge the two JSON dataobjects, and remove the duplicate start field items. 我的方法将太过合并两个JSON数据对象,并删除重复的开始字段项。
Sample Implementation in JQuery: JQuery中的示例实现:
Lets say you append both the lists into one list called mergedItems then 假设您将两个列表都附加到一个称为mergedItems的列表中,然后
var uniqueItems = [];
$.each(mergedItems["start"], function(i, el){
if($.inArray(el, uniqueItems ) === -1) uniqueItems.push(el);
});
Edit: Working Example 编辑:工作示例
http://jsbin.com/vakodahile/edit?html,js,output http://jsbin.com/vakodahile/edit?html,js,输出
There is a handy javascript library http://underscorejs.org/ that you can use for this. 有一个方便的javascript库http://underscorejs.org/可用于此目的。 It's not exactly join, but it accomplishes the task with a single loop. 它不是完全联接,但它可以通过一个循环来完成任务。
_.each(jQuery.parseJSON(json), function(d){
console.log(d.start)
var idx = _.findIndex(array_of_all_dates, function(ad){ return d.start == ad.start });
if(idx>-1){
array_of_all_dates[idx] = d;
}
});
I did notice there there were no matches because your date formats don't match exactly. 我确实注意到没有匹配项,因为您的日期格式不完全匹配。 You can try instantiating a new moment object in the findIndex
predicate and specify a specific datetime format. 您可以尝试在findIndex
谓词中实例化新的moment对象,并指定特定的日期时间格式。
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