[英]python how to transfer between a list of integers and string of bits?
I have a list of integers, each integer in range [0,255]. 我有一个整数列表,每个整数的范围为[0,255]。 I want to transfer this into a string of bits. 我想将其转换为一串位。 Each integer use 8 bits to represent. 每个整数使用8位表示。 After I handle string of bits, I want to transfer it into a list of integers, every 8-bit to a integer. 处理完位字符串后,我想将其转换为整数列表,每8位转换为一个整数。 How to do it? 怎么做?
You don't need external library. 您不需要外部库。 Use python's built-in function. 使用python的内置函数。
integer to binary: 整数到二进制:
i = 100
print "{0:08b}".format(i)
binary to integer: 二进制到整数:
b = "01100100"
print int(b, 2)
If you need to build a large bit array, then using bitarray
module is good, as what you did in your answer: 如果您需要构建一个大的位数组,那么使用bitarray
模块就可以了,就像您在答案中所做的那样:
bits = bitarray()
for i in pixels: bits.extend("{0:08b}".format(i))
I have got the answer. 我有答案。 This is my answer: 这是我的答案:
from PIL import Image
from bitarray import bitarray
from bitstring import BitArray
class Compress:
def readFile(self, filename):
self.img = Image.open(filename)
self.pixels = list(self.img.getdata()) # a list of int--[0,255]
def __toBitArray__(self):
self.bits = bitarray()
for i in self.pixels:
self.bits.extend(BitArray(uint=i, length=8).bin)
print(self.bits.length())
def saveFile(self, filename):
p = []
for i in range(self.bits.length()//8):
b = self.bits[i*8:i*8+8].to01()
p.append(BitArray(bin=b).uint)
self.img.putdata(p)
self.img.save(filename)
self.img.close()
if __name__ == '__main__':
c = Compress()
c.readFile('num.bmp')
c.__toBitArray__()
c.saveFile('test.bmp')
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